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Evaporation in Double-Effect Reverse-Feed Evaporators. A feed containing 2 wt % dissolved organic solids in water is fed to a double-effect evaporator with reverse feed. The feed enters at 100°F and is concentrated to 25% solids. The boiling-point rise can be considered negligible as well as the heat of solution. Each evaporator has a 1000-ft2 surface area and the heat-transfer coefficients are U, = evaporator number 2 and steam at 100 psia is fed to number 1. The pressure in the vapor space of evaporator number 2 is 0.98 psia. Assume that the heat capacity of all liquid solutions is that of liquid water. Calculate the feed rate F and the product rate L, of a solution containing 25% solids. (Hint: Assume a feed rate of, say, F = 1000 lb„/h. Calculate the area. Then calculate the actual feed rate by multiplying 1000 by 1000/calculated area.) 500 and Uz = 700 btu/h ft?.°F. The feed enters %D m Ans. F = 133 800 lbm/h (60 691 kg/h), L, 10 700 lb.„/h (4853 kg/h)

Evaporation in Double-Effect Reverse-Feed Evaporators. A feed containing 2 wt % dissolved organic solids in water is fed to a double-effect evaporator with reverse feed. The feed enters at 100°F and is concentrated to 25% solids. The boiling-point rise can be considered negligible as well as the heat of solution. Each evaporator has a 1000-ft2 surface area and the heat-transfer coefficients are U, = evaporator number 2 and steam at 100 psia is fed to number 1. The pressure in the vapor space of evaporator number 2 is 0.98 psia. Assume that the heat capacity of all liquid solutions is that of liquid water. Calculate the feed rate F and the product rate L, of a solution containing 25% solids. (Hint: Assume a feed rate of, say, F = 1000 lb„/h. Calculate the area. Then calculate the actual feed rate by multiplying 1000 by 1000/calculated area.) 500 and Uz = 700 btu/h ft?.°F. The feed enters %D m Ans. F = 133 800 lbm/h (60 691 kg/h), L, 10 700 lb.„/h (4853 kg/h)

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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8.5-3. Evaporation in Double-Effect Reverse-Feed Evaporators. A feed containing 2 wt % dissolved organic solids in water is fed to a double-effect evaporator with reverse feed. The feed enters at 100°F and is concentrated to 25% solids. The boiling-point rise can be considered negligible as well as the heat of solution. Each evaporator has a 1000-ft2 surface area and the heat-transfer coefficients are U evaporator number 2 and steam at 100 psia is fed to number 1. The pressure in the vapor space of evaporator number 2 is 0.98 psia. Assume that the heat capacity of all liquid solutions is that of liquid water. Calculate the feed rate F and the product rate L, of a solution containing 25% solids. (Hint: Assume a feed rate of, say, F = 1000 lbm/h. Calculate the area. Then calculate the actual feed rate by multiplying 1000 by 1000/calculated area.) = 500 and U2 = 700 btu/h•ft.°F. The feed enters Ans. F = 133 800 lb,m/h (60 691 kg/h), L, 10 700 lb„/h (4853 kg/h)
Transcribed Image Text:8.5-3. Evaporation in Double-Effect Reverse-Feed Evaporators. A feed containing 2 wt % dissolved organic solids in water is fed to a double-effect evaporator with reverse feed. The feed enters at 100°F and is concentrated to 25% solids. The boiling-point rise can be considered negligible as well as the heat of solution. Each evaporator has a 1000-ft2 surface area and the heat-transfer coefficients are U evaporator number 2 and steam at 100 psia is fed to number 1. The pressure in the vapor space of evaporator number 2 is 0.98 psia. Assume that the heat capacity of all liquid solutions is that of liquid water. Calculate the feed rate F and the product rate L, of a solution containing 25% solids. (Hint: Assume a feed rate of, say, F = 1000 lbm/h. Calculate the area. Then calculate the actual feed rate by multiplying 1000 by 1000/calculated area.) = 500 and U2 = 700 btu/h•ft.°F. The feed enters Ans. F = 133 800 lb,m/h (60 691 kg/h), L, 10 700 lb„/h (4853 kg/h)
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