(2.11) A graphite heat exchanger is constructed by drilling circular channels in a solid block of graphite. Consider a large graphite block (k = 800 W/m K) containing two 1-in. diameter channels spaced 2 in. apart (center-to-center). A highly corrosive liquid (T=350°F, h=120 Btu/h ft2 °F) flows through one channel and a coolant (T= 170°F, h=200 Btu/h ft² °F) flows in the other channel. Calculate the rate of heat transfer from the corrosive liquid to the coolant per foot of exchanger length. Ans. 3470 Btu/h ft of length.
(2.11) A graphite heat exchanger is constructed by drilling circular channels in a solid block of graphite. Consider a large graphite block (k = 800 W/m K) containing two 1-in. diameter channels spaced 2 in. apart (center-to-center). A highly corrosive liquid (T=350°F, h=120 Btu/h ft2 °F) flows through one channel and a coolant (T= 170°F, h=200 Btu/h ft² °F) flows in the other channel. Calculate the rate of heat transfer from the corrosive liquid to the coolant per foot of exchanger length. Ans. 3470 Btu/h ft of length.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:(2.11) A graphite heat exchanger is constructed by drilling circular channels in a solid block of graphite. Consider a large graphite
block (k = 800 W/m K) containing two 1-in. diameter channels spaced 2 in. apart (center-to-center). A highly corrosive liquid
(T=350°F, h = 120 Btu/h ft² °F) flows through one channel and a coolant (T= 170°F, h=200 Btu/h ft² °F) flows in the
other channel. Calculate the rate of heat transfer from the corrosive liquid to the coolant per foot of exchanger length.
Ans. 3470 Btu/h ft of length.
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