) Evaluate √x² + y²dA where D is the region bounded by the polar curve r = 2 cos. Sketch the region. D

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Problem 5:**
Evaluate the double integral 

\[
\iint_D \sqrt{x^2 + y^2} \, dA
\]

where \( D \) is the region bounded by the polar curve \( r = 2 \cos \theta \). Sketch the region.

**Explanation:**  
The problem involves evaluating the given double integral over the region \( D \) defined by the polar curve \( r = 2 \cos \theta \), which is a circle with a radius of 1 centered at \( (1,0) \) on the polar coordinate plane. To solve this, one can convert the integral into polar coordinates, where \( x = r \cos \theta \) and \( y = r \sin \theta \).

**Sketch:**  
The region to sketch is a circle with its center at \( (1,0) \) and a radius of 1. The curve \( r = 2 \cos \theta \) represents this circle.
Transcribed Image Text:**Problem 5:** Evaluate the double integral \[ \iint_D \sqrt{x^2 + y^2} \, dA \] where \( D \) is the region bounded by the polar curve \( r = 2 \cos \theta \). Sketch the region. **Explanation:** The problem involves evaluating the given double integral over the region \( D \) defined by the polar curve \( r = 2 \cos \theta \), which is a circle with a radius of 1 centered at \( (1,0) \) on the polar coordinate plane. To solve this, one can convert the integral into polar coordinates, where \( x = r \cos \theta \) and \( y = r \sin \theta \). **Sketch:** The region to sketch is a circle with its center at \( (1,0) \) and a radius of 1. The curve \( r = 2 \cos \theta \) represents this circle.
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