Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![### Problem Statement:
**Evaluate the triple integral:**
\[
\iiint\limits_E y \, dV
\]
where \( E = \{ (x, y, z) \mid 0 \leq x \leq 5, \, 0 \leq y \leq x, \, x-y \leq z \leq x+y \} \).
### Explanation:
This problem involves evaluating a triple integral over a specific region \( E \) in three-dimensional space. The limits for the variables \( x, y, \) and \( z \) are given as:
- \( 0 \leq x \leq 5 \)
- \( 0 \leq y \leq x \)
- \( x-y \leq z \leq x+y \)
To solve this integral, you will need to integrate \( y \) with respect to \( z \), \( y \), and \( x \) in that order, over the region defined by the inequalities. The innermost integral is with respect to \( z \), which is bounded by the expressions \( x-y \) and \( x+y \). The middle integral is with respect to \( y \), bounded between 0 and \( x \). The outermost integral is with respect to \( x \), bounded from 0 to 5.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F76a66a71-ada1-45a3-b975-e1c2879a1133%2F65733548-ff65-4a33-b26e-5c9e106b9e55%2Fo3yybxm_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem Statement:
**Evaluate the triple integral:**
\[
\iiint\limits_E y \, dV
\]
where \( E = \{ (x, y, z) \mid 0 \leq x \leq 5, \, 0 \leq y \leq x, \, x-y \leq z \leq x+y \} \).
### Explanation:
This problem involves evaluating a triple integral over a specific region \( E \) in three-dimensional space. The limits for the variables \( x, y, \) and \( z \) are given as:
- \( 0 \leq x \leq 5 \)
- \( 0 \leq y \leq x \)
- \( x-y \leq z \leq x+y \)
To solve this integral, you will need to integrate \( y \) with respect to \( z \), \( y \), and \( x \) in that order, over the region defined by the inequalities. The innermost integral is with respect to \( z \), which is bounded by the expressions \( x-y \) and \( x+y \). The middle integral is with respect to \( y \), bounded between 0 and \( x \). The outermost integral is with respect to \( x \), bounded from 0 to 5.
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