Evaluate the solution The problem: A 2.0 kg cart with a +3.0x10-5 C charge on it sits at rest 1.0 m to the right of a fixed sphere with charge 1.5x10-4 C. The cart is released. Determine how fast it is going at 3.0 m. Proposed solution: There is a net force to the right. According to Newton’s 2nd Law and Coulomb’s law, the acceleration is given by: � = �

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Evaluate the solution The problem: A 2.0 kg cart with a +3.0x10-5 C charge on it sits at rest 1.0 m to the right of a fixed sphere with charge 1.5x10-4 C. The cart is released. Determine how fast it is going at 3.0 m. Proposed solution: There is a net force to the right. According to Newton’s 2nd Law and Coulomb’s law, the acceleration is given by: � = ��!�" �� = (9 × 10#)(3 × 10$%�)(1.5 × 10$&�) (2��)(1�) = 20.3�/�" The speed can be found from a kinematic equation: - - +++++++ +++++++ - + v2 = 0 + 2(20.3)(3m −1m) or a speed of 9m/s. Indicate any missing or incorrect elements. Provide a corrected solution.
4) Evaluate the solution
The problem: A 2.0 kg cart with a +3.0x105 C charge on it sits at rest 1.0 m to the right of a fixed
sphere with charge 1.5x10-4 C. The cart is released. Determine how fast it is going at 3.0 m.
Proposed solution: There is a net force to the right. According to Newton's 2nd Law and
Coulomb's law, the acceleration is given by:
kq192 _ (9 × 10º)(3 × 10−5℃)(1.5 × 10−4C)
a
mr
(2kg) (1m)
The speed can be found from a kinematic equation:
v²=0+2(20.3)(3m-1m) or a speed of 9m/s.
= 20.3m/s²
Indicate any missing or incorrect elements. Provide a corrected solution.
Transcribed Image Text:4) Evaluate the solution The problem: A 2.0 kg cart with a +3.0x105 C charge on it sits at rest 1.0 m to the right of a fixed sphere with charge 1.5x10-4 C. The cart is released. Determine how fast it is going at 3.0 m. Proposed solution: There is a net force to the right. According to Newton's 2nd Law and Coulomb's law, the acceleration is given by: kq192 _ (9 × 10º)(3 × 10−5℃)(1.5 × 10−4C) a mr (2kg) (1m) The speed can be found from a kinematic equation: v²=0+2(20.3)(3m-1m) or a speed of 9m/s. = 20.3m/s² Indicate any missing or incorrect elements. Provide a corrected solution.
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