Evaluate the line integral (xyds where C is the line segment from (0,0,1) to (2,3,5). от

Evaluate the line integral 3xy ds where C is the Segment Joining (-5,7) to (3,1) line Segment

Evaluate the line integral -ydx + xdy along the curve С: у? 3 15х from (15, 15) to (0, 0). NOTE: Enter the exact answer. -ydx + xdy =

Find b∈R so that ∫C4x^2dy − 2xydx = 53, where C is the segment from (1, −5) to (−2, −3), followed by the part of y = 1 − x^2 from x = −2 ax = 2, followed by the segment from (2, −3) to (4, b).