Evaluate the curve/line integral (2, 4) to (4,4). If curve C = C1+C₂, it is true that Check Answer/Save 16³ 3z da where C = C₁+C₂ with C₁ representing the curve y = z² from (0,0) to (2,4) and C₂ is the horizontal line y = 4 from 0 (2,9) de-1(z,y) de-f(x,y) de da ✔ [1(2₁v) de f(x,y) de +1(z,y) de = = 0 [ 1(2₁4) da = [ 1(2₁1) de -f(v.2) da z) 0 == f(x,y) da = -f(z,y) da - | f(z,y) da C₂ Step-By-Step Example Answer format: Enter the value If you integrate along curve C₁ What is the value of Live Help dz dt + dy dt X assuming t is the parameter:

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
What is the value of
2
Ja
Answer format: Enter the value
Check Answer/Save
6
What is the value of
3ads:
10³
Check Answer/Save
Step-By-Step Example
3rds:
Answer format: Enter a number
Step-By-Step Example
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Live Help
B
X
X
Transcribed Image Text:What is the value of 2 Ja Answer format: Enter the value Check Answer/Save 6 What is the value of 3ads: 10³ Check Answer/Save Step-By-Step Example 3rds: Answer format: Enter a number Step-By-Step Example Live Help Live Help B X X
Evaluate the curve/line integral
(2, 4) to (4,4).
If curve C = C₁+C₂, it is true that
Check Answer/Save
1²
3x ds where C = C₁+C₂ with C, representing the curve y = z² from (0,0) to (2, 4) and C₂ is the horizontal line y = 4 from
✔
Check Answer/Save
(2.) de-1(₁) de-1(v) de
(2.v) de-f(z,y) de + f(z,y) da
[1(z,y) da = f(z,y) de -f(v.2) da
(z,y) da = -f(2,v) da-f(z,y) da
Step-By-Step Example
If you integrate along curve C₁ What is the value of
Answer format: Enter the value
Step-By-Step Example
Live Help
dz
dt
+
Live Help
dy
dt
X
2
assuming t is the parameter:
Transcribed Image Text:Evaluate the curve/line integral (2, 4) to (4,4). If curve C = C₁+C₂, it is true that Check Answer/Save 1² 3x ds where C = C₁+C₂ with C, representing the curve y = z² from (0,0) to (2, 4) and C₂ is the horizontal line y = 4 from ✔ Check Answer/Save (2.) de-1(₁) de-1(v) de (2.v) de-f(z,y) de + f(z,y) da [1(z,y) da = f(z,y) de -f(v.2) da (z,y) da = -f(2,v) da-f(z,y) da Step-By-Step Example If you integrate along curve C₁ What is the value of Answer format: Enter the value Step-By-Step Example Live Help dz dt + Live Help dy dt X 2 assuming t is the parameter:
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