Evaluate the integrals through INTEGRATION BY PARTS only (Sudv=uv- fvdu.) Apply trigonometric integrals and Integration by Trigonometric Substitution. |-9+ 16* -dx 1. 16* 2. arctan(Vx – 2)dx sin x cos® x 3. -dx use this REFERENCE of trig integrals: | sin" xdx, where meNand m is odd • split off a factor of sinx • express the rest of the factors in terms of cos.x using sin? x = 1- cos² x • use the substitution u = cos.x, du=-sin.xdx • | sinx dx= - cos.x+ C • | cosx dx= sin.x+ C sin"xdx or cos" xdx, where meNand mis even • S sin° x dx= [a - 1 1 cos2x) dx= -x- sin2x+ C 2 4 • express sin"x= (sin² x)m/2 or cos" x= (cos²x)m/2 • use the half-angle identity | cos? x dx = (1+ cos 2.x) dx=-x+ sin2.x+C 1 %3D 1

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Evaluate the integrals through INTEGRATION BY PARTS only (Sudv=uv- fvdu.)
Apply trigonometric integrals and Integration by Trigonometric Substitution.
|-9+ 16*
-dx
1.
16*
2.
arctan(Vx – 2)dx
sin x
cos® x
3.
-dx
use this REFERENCE of trig integrals:
| sin" xdx, where meNand m is odd
• split off a factor of sinx
• express the rest of the factors in terms of cos.x using sin? x = 1- cos² x
• use the substitution u = cos.x, du=-sin.xdx
• | sinx dx= - cos.x+ C
• | cosx dx= sin.x+ C
1
sin"xdx or cos" xdx, where meNand mis even
sin’ x dx=
1
cos2x) dx= ÷x-sin2x+ C
2
4
• express sin"x= (sin² x)™/2
• use the half-angle identity
or cos"x= (cos²x)/2
1
1
• | cos²x dx =
(1+ cos 2.x) dx=-x+- sin2.x+ C
2 4
cos x=(1+cos 2.x) or sin?x=÷(1-cos2.x)
REFERENCE cases for trig substitution:
Case 1. Va² – ư² =let u= asin0, so vď² – u² = acos
%3D
Case 2. Vư – a² =let u= asec0, so vư – á = atan0
Case 3. Va? + u² =let u= atan0, so va²2+ u² = asec0
Transcribed Image Text:Evaluate the integrals through INTEGRATION BY PARTS only (Sudv=uv- fvdu.) Apply trigonometric integrals and Integration by Trigonometric Substitution. |-9+ 16* -dx 1. 16* 2. arctan(Vx – 2)dx sin x cos® x 3. -dx use this REFERENCE of trig integrals: | sin" xdx, where meNand m is odd • split off a factor of sinx • express the rest of the factors in terms of cos.x using sin? x = 1- cos² x • use the substitution u = cos.x, du=-sin.xdx • | sinx dx= - cos.x+ C • | cosx dx= sin.x+ C 1 sin"xdx or cos" xdx, where meNand mis even sin’ x dx= 1 cos2x) dx= ÷x-sin2x+ C 2 4 • express sin"x= (sin² x)™/2 • use the half-angle identity or cos"x= (cos²x)/2 1 1 • | cos²x dx = (1+ cos 2.x) dx=-x+- sin2.x+ C 2 4 cos x=(1+cos 2.x) or sin?x=÷(1-cos2.x) REFERENCE cases for trig substitution: Case 1. Va² – ư² =let u= asin0, so vď² – u² = acos %3D Case 2. Vư – a² =let u= asec0, so vư – á = atan0 Case 3. Va? + u² =let u= atan0, so va²2+ u² = asec0
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