Evaluate the integrals: 1. 2. -2 dx 0 8+2x² x+3 2x3-8x S - dx

Q: dx 5x. J 75V9x² – 1

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Q: 6 dx. 1+ 9x2 Calculate

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Q: Which is NOT included in evaluating the integral? (Use partial fraction decomposition method.) 4 2x…

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Q: 3 + 2/5x-3 dx. Find 4x+1 - Vez

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Q: 1 dx (2x + 1)4

A: We will use concept of improper integral here.

Q: Evaluate f(4 – 3x)³ dr

A: The integration of the (4-3x)3 and limit from 1 to 2.

Q: f. S r4 dx J2 xV2-2x2 2.

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Q: S Vx8 – 6x6 + 9x4 dx is equal to -

A: The equation of integral is ∫x8-6x6+9x4dx.

Q: Calculate 2 3x-2x²+2 dx. 13 -1

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Q: x2+1 - dx x4-x²+1

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Q: 2 dx 8x + 9

A: To find the value of given integration  We use some basic results of integration and substitution

Q: 2 dx 43.

A: Given integral is

Q: Compute 3+r+1 dx x2

A: Given : ∫233x2+2x+1x2dx

Q: dx 4. / TV²+ 4x – 4 4х — 4

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Q: -dx x +1 2 5.

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Q: 1 10. dx x² Vx² – 4 -

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Q: Evaluate 4xcos 3x dx by using integration by part.

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Q: 1 dx Va? – 6x + 34 Find -

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Q: 4 dx V1- 25x2

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Q: 1 dx 4+vx 10.

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Q: 2 dx Evaluate J xvx4 + 25

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Q: 3 dx 4+x2 00 Find

A: Let I=∫2∞34+x2dx. Simplify the integration I by using the constant multiple rule.…

Q: Evaluate. 4 ' - 6Vx +x 3 dx - 6x +x 3 dx =

A: We have to evaluate the given integral. Please recall the famous rule of integration: Integral of…

Q: d 0.6 56. 2.8x -3. dx

A: Differentiate

Q: -5х? —16х + 28 dx te x' -4x

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