Evaluate the integral. Select the correct answer. 1 15 cos ²6 x - = cos 6x + C cos³6 6x- 18 O sin³6x-sin 6x + C // sin 6 x - sin³6x + C 18 24 cos* 6x-√2 cos²x+c 6x- 1 O sin 6x-2 sin ²6x + C ㅎ sin³6x 12 O cos 6x - 7B cos³6x + C ㅇㅎ 18 1 4 24 sin * 6x - 725 12 sin ²6 x + C sin³6 x dx
Evaluate the integral. Select the correct answer. 1 15 cos ²6 x - = cos 6x + C cos³6 6x- 18 O sin³6x-sin 6x + C // sin 6 x - sin³6x + C 18 24 cos* 6x-√2 cos²x+c 6x- 1 O sin 6x-2 sin ²6x + C ㅎ sin³6x 12 O cos 6x - 7B cos³6x + C ㅇㅎ 18 1 4 24 sin * 6x - 725 12 sin ²6 x + C sin³6 x dx
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![### Evaluate the integral.
\[
\int \sin^3(6x) \, dx
\]
### Select the correct answer.
- ( ) \(\frac{1}{18} \cos^3(6x) - \frac{1}{6} \cos(6x) + C\)
- ( ) \(\frac{1}{18} \sin^3(6x) - \frac{1}{6} \sin(6x) + C\)
- ( ) \(\frac{1}{6} \sin(6x) - \frac{1}{18} \sin^3(6x) + C\)
- ( ) \(\frac{1}{24} \cos^4(6x) - \frac{1}{12} \cos^2(6x) + C\)
- ( ) \(\frac{1}{6} \sin(6x) - \frac{1}{12} \sin^3(6x) + C\)
- ( ) \(\frac{1}{6} \cos(6x) - \frac{1}{18} \cos^6(6x) + C\)
- ( ) \(\frac{1}{24} \sin^4(6x) - \frac{1}{12} \sin^2(6x) + C\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F24e8bfde-46ac-4815-81bc-d8be1d9c4f35%2Fb05de946-3f84-44bd-b8f2-bd3b5c919190%2F0ubtks_processed.png&w=3840&q=75)
Transcribed Image Text:### Evaluate the integral.
\[
\int \sin^3(6x) \, dx
\]
### Select the correct answer.
- ( ) \(\frac{1}{18} \cos^3(6x) - \frac{1}{6} \cos(6x) + C\)
- ( ) \(\frac{1}{18} \sin^3(6x) - \frac{1}{6} \sin(6x) + C\)
- ( ) \(\frac{1}{6} \sin(6x) - \frac{1}{18} \sin^3(6x) + C\)
- ( ) \(\frac{1}{24} \cos^4(6x) - \frac{1}{12} \cos^2(6x) + C\)
- ( ) \(\frac{1}{6} \sin(6x) - \frac{1}{12} \sin^3(6x) + C\)
- ( ) \(\frac{1}{6} \cos(6x) - \frac{1}{18} \cos^6(6x) + C\)
- ( ) \(\frac{1}{24} \sin^4(6x) - \frac{1}{12} \sin^2(6x) + C\)
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