Evaluate the integral dy dx. Va/3 We reverse the order of integration to obtain 3 3y2 dy •1 ev dy dx ¤/3 dy = / dx 1 3y?ev dy = e – 1 1.5- 1- 0.5 0.5 1.5 2.5

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Chapter2: Second-order Linear Odes
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Can you explain step by step how the new bounds are found. **Note question is already answered

r3
Evaluate the integral
dy dx.
x/3
We reverse the order of integration to obtain
3
1
3y²
1
3y2
dy =
dy dx
dx
dy
/x/3
dy
ее —
1
1.5
1-
0.5
0.5
1.5
2.5
3
Transcribed Image Text:r3 Evaluate the integral dy dx. x/3 We reverse the order of integration to obtain 3 1 3y² 1 3y2 dy = dy dx dx dy /x/3 dy ее — 1 1.5 1- 0.5 0.5 1.5 2.5 3
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