Evaluate the integral 1 12 3x (x - 1) dx 0.

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A: Given

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Q: Evaluate x(x2 + 1)3 dx.

A: Given ∫x(x2+1)3dx

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A: We can find the integration as below.

Q: x + 1 -xp- x + 3 x2 + 2x – 3 x2 3 dx ,

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Q: Evaluate x +1 dx x2 (x – 1) - 2.

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Q: 1 + 2x dx 1

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Q: Evaluate х2 + 2х — 1 х3 — х

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Q: -3x² - 4x + 3 1 x (x + 1)² dx

A: Given problem:-

Q: -5х? —16х + 28 dx te x' -4x

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Q: 4x dx (1-x²)³

A: