Evaluate the following integral using integration by parts. Sox 9x dx 8x e

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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8.2.   5

 

### Integration by Parts: Example Problem

#### Problem Statement

Evaluate the following integral using integration by parts:

\[ \int 8x \, e^{9x} \, dx \]

#### Solution Process

Use the integration by parts formula so that the new integral is simpler than the original one. The integration by parts formula is:

\[ \int u \, dv = uv - \int v \, du \]

### Applying Integration by Parts

Given the integral:

\[ \int 8x \, e^{9x} \, dx \]

Let's choose:
- \( u = 8x \)
- \( dv = e^{9x} \, dx \)

Now, we need to find \( du \) and \( v \):

\[ du = 8 \, dx \]
\[ v = \int e^{9x} \, dx = \frac{1}{9} e^{9x} \]

Using the integration by parts formula:

\[ \int 8x \, e^{9x} \, dx = u \cdot v - \int v \, du \]

Substitute the expressions for \( u \), \( v \), and \( du \):

\[ \int 8x \, e^{9x} \, dx = 8x \cdot \frac{1}{9} e^{9x} - \int \frac{1}{9} e^{9x} \cdot 8 \, dx \]

Simplify the expression:

\[ \int 8x \, e^{9x} \, dx = \frac{8}{9} x \, e^{9x} - \frac{8}{9} \int e^{9x} \, dx \]

Evaluate the remaining integral:

\[ \int e^{9x} \, dx = \frac{1}{9} e^{9x} \]

Hence, the expression becomes:

\[ \int 8x \, e^{9x} \, dx = \frac{8}{9} x \, e^{9x} - \frac{8}{9} \cdot \frac{1}{9} e^{9x} \]

Simplify:

\[ \int 8x \, e^{9x} \, dx = \frac{8}{9} x \, e^{9x} - \frac{8
Transcribed Image Text:### Integration by Parts: Example Problem #### Problem Statement Evaluate the following integral using integration by parts: \[ \int 8x \, e^{9x} \, dx \] #### Solution Process Use the integration by parts formula so that the new integral is simpler than the original one. The integration by parts formula is: \[ \int u \, dv = uv - \int v \, du \] ### Applying Integration by Parts Given the integral: \[ \int 8x \, e^{9x} \, dx \] Let's choose: - \( u = 8x \) - \( dv = e^{9x} \, dx \) Now, we need to find \( du \) and \( v \): \[ du = 8 \, dx \] \[ v = \int e^{9x} \, dx = \frac{1}{9} e^{9x} \] Using the integration by parts formula: \[ \int 8x \, e^{9x} \, dx = u \cdot v - \int v \, du \] Substitute the expressions for \( u \), \( v \), and \( du \): \[ \int 8x \, e^{9x} \, dx = 8x \cdot \frac{1}{9} e^{9x} - \int \frac{1}{9} e^{9x} \cdot 8 \, dx \] Simplify the expression: \[ \int 8x \, e^{9x} \, dx = \frac{8}{9} x \, e^{9x} - \frac{8}{9} \int e^{9x} \, dx \] Evaluate the remaining integral: \[ \int e^{9x} \, dx = \frac{1}{9} e^{9x} \] Hence, the expression becomes: \[ \int 8x \, e^{9x} \, dx = \frac{8}{9} x \, e^{9x} - \frac{8}{9} \cdot \frac{1}{9} e^{9x} \] Simplify: \[ \int 8x \, e^{9x} \, dx = \frac{8}{9} x \, e^{9x} - \frac{8
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