Evaluate the commutator [y², 82/8x² +82/8y2] by applying the operators to an arbitrary function f(x, y). Match the items in the left column to the appropriate blanks in the equations on the right. Make certain each equation is complete before submitting your answer. & [y²f(x, y) + y² ºf(2,y)] 4y² [2yf(x, y) + y²! 2y y² 2 0f(s) by 2y² [y² f(x, y) + y ² 0²³f(x,y)] 4y [y², 0²/0x² + 0²/0y2²]f(x, y) = y²(0²/0x² + 0²/Əy²) f(x, y) - (0²/0x² + 0²/0y²)y² f(x, y) 0² f(x, y) ( a² f(x, y) + a² f(x, y)) მ2 əx² 8² f(x, y) მ2 2 0² f(x, y) ?х2 +y² af(x, y) dy y² y ?х2 8² f(x, y) ?х2 8² f(x, y) dy² f(x, y) - Therefore, [y2, 02/0x² + 0²/0y²] = - af(x, y) dy f(x, y) - Reset Help Ə dy af(x, y) dy
Evaluate the commutator [y², 82/8x² +82/8y2] by applying the operators to an arbitrary function f(x, y). Match the items in the left column to the appropriate blanks in the equations on the right. Make certain each equation is complete before submitting your answer. & [y²f(x, y) + y² ºf(2,y)] 4y² [2yf(x, y) + y²! 2y y² 2 0f(s) by 2y² [y² f(x, y) + y ² 0²³f(x,y)] 4y [y², 0²/0x² + 0²/0y2²]f(x, y) = y²(0²/0x² + 0²/Əy²) f(x, y) - (0²/0x² + 0²/0y²)y² f(x, y) 0² f(x, y) ( a² f(x, y) + a² f(x, y)) მ2 əx² 8² f(x, y) მ2 2 0² f(x, y) ?х2 +y² af(x, y) dy y² y ?х2 8² f(x, y) ?х2 8² f(x, y) dy² f(x, y) - Therefore, [y2, 02/0x² + 0²/0y²] = - af(x, y) dy f(x, y) - Reset Help Ə dy af(x, y) dy
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Evaluate the commutator [y², 0²/0x² + 0²/0y²] by applying the operators to an arbitrary function f(x, y).
Match the items in the left column to the appropriate blanks in the equations on the right. Make certain each equation is complete before submitting your answer.
Ə
dy
dy
2
y² f(x, y) + y²
4y²
2yf(x, y) + y²
,2
2y
y²
2
af(x,y)
dy
Of(x,y)
dy
2y²
[y²f(x, y) + y² 8² f(x,y)
მყ2
4y
[y², 0² / əx² + 0²/Əy²]ƒ(x, y) = y² (8² / əx² + ə² /Əy²) ƒ(x, y) — (Ə² /Əx² + 0² /Əy²)y²ƒ(x, y)
-
= y²/
=
= y²
a² f(x, y) a² f(x, y).
‚ə² ƒ(x, y)
3² f(x, y))
+
2
дуг
+
a² f(x, y)
dy²
Əx²
0² f(x, y)
მ2
2
+y².
əx²
‚a² f(x, y)
əx²
-y².
2
f(x, y) ₂a² f(x, y)
- y².
2
მყ
მყ2
f(x, y)
Therefore, [y², 0²/0x² + 0²/Əy²]
Of(x, y)
ду
f(x, y) —
Reset Help
ду
af(x, y)
ду](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faa93ff2f-dc04-4549-9d2f-0f80a4020e3f%2F051e01de-b8e6-4f47-b91a-dc48b1c0f205%2Fkufl1qm_processed.png&w=3840&q=75)
Transcribed Image Text:Evaluate the commutator [y², 0²/0x² + 0²/0y²] by applying the operators to an arbitrary function f(x, y).
Match the items in the left column to the appropriate blanks in the equations on the right. Make certain each equation is complete before submitting your answer.
Ə
dy
dy
2
y² f(x, y) + y²
4y²
2yf(x, y) + y²
,2
2y
y²
2
af(x,y)
dy
Of(x,y)
dy
2y²
[y²f(x, y) + y² 8² f(x,y)
მყ2
4y
[y², 0² / əx² + 0²/Əy²]ƒ(x, y) = y² (8² / əx² + ə² /Əy²) ƒ(x, y) — (Ə² /Əx² + 0² /Əy²)y²ƒ(x, y)
-
= y²/
=
= y²
a² f(x, y) a² f(x, y).
‚ə² ƒ(x, y)
3² f(x, y))
+
2
дуг
+
a² f(x, y)
dy²
Əx²
0² f(x, y)
მ2
2
+y².
əx²
‚a² f(x, y)
əx²
-y².
2
f(x, y) ₂a² f(x, y)
- y².
2
მყ
მყ2
f(x, y)
Therefore, [y², 0²/0x² + 0²/Əy²]
Of(x, y)
ду
f(x, y) —
Reset Help
ду
af(x, y)
ду
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