Evaluate e(x2 + y2 + z2)3/2 where B is the ball: EXAMPLE 3 {(x, y, z) x² + y? + z² <4. B = 3 SOLUTION Since the boundary of B is a sphere, we use spherical coordinates: = {(e, 0, 4) 0s p s 2,0 s 0 s 21, 0 < 4 < In addition, spherical coordinates are appropriate because x² + y2 + z² = p². Thus this equation gives e(x2. + y2 + z2)3/2 elp?}3/2 dp d0 do de p?ep3 dp TT (2t)
Evaluate e(x2 + y2 + z2)3/2 where B is the ball: EXAMPLE 3 {(x, y, z) x² + y? + z² <4. B = 3 SOLUTION Since the boundary of B is a sphere, we use spherical coordinates: = {(e, 0, 4) 0s p s 2,0 s 0 s 21, 0 < 4 < In addition, spherical coordinates are appropriate because x² + y2 + z² = p². Thus this equation gives e(x2. + y2 + z2)3/2 elp?}3/2 dp d0 do de p?ep3 dp TT (2t)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![e(x2
+ y2 + z2)3/2 where B is the ball:
EXAMPLE 3
Evaluate
= {(x, y, z) x² + y2+ z² s
(х, у, 2)
В —
SOLUTION
Since the boundary of B is a sphere, we use spherical coordinates:
(ρ, θ, φ) 0 < ρ < 2, 0 <θ 2π, 0<φ= π.
В —
In addition, spherical coordinates are appropriate because
x2 + y2 + z? = p².
Thus this equation gives
e(x2.
+ y2 + z2)3/2
elp2}3/2
dp de dp
2
dp
de
p²ep3
dp](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe5f558a7-14fc-4024-84d6-4debb1adc6f6%2F5397c978-a9f4-4125-8306-2e07160a151c%2Fg5qgbr6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:e(x2
+ y2 + z2)3/2 where B is the ball:
EXAMPLE 3
Evaluate
= {(x, y, z) x² + y2+ z² s
(х, у, 2)
В —
SOLUTION
Since the boundary of B is a sphere, we use spherical coordinates:
(ρ, θ, φ) 0 < ρ < 2, 0 <θ 2π, 0<φ= π.
В —
In addition, spherical coordinates are appropriate because
x2 + y2 + z? = p².
Thus this equation gives
e(x2.
+ y2 + z2)3/2
elp2}3/2
dp de dp
2
dp
de
p²ep3
dp
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