Ethyl heptanoate (EH), a food aroma compound, was added to water and allowed to come to equilibrium with a known volume of air and results showed that its partition coefficient, [EH»«]/[EHwater] is equal to 1.8 x 10-2. In the same experiment with oil in place of water, its partition coefficient, [EHair]/[EHo] is found to be lower at 6.0 x 106. Account for the difference
Ethyl heptanoate (EH), a food aroma compound, was added to water and allowed to come to equilibrium with a known volume of air and results showed that its partition coefficient, [EH»«]/[EHwater] is equal to 1.8 x 10-2. In the same experiment with oil in place of water, its partition coefficient, [EHair]/[EHo] is found to be lower at 6.0 x 106. Account for the difference
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Ethyl heptanoate (EH), a food aroma compound, was added to
water and allowed to come to equilibrium with a known
volume of air and results showed that its partition coefficient,
[EHair]/[EHwater] is equal to 1.8 x 10-2. In the same experiment
with oil in place of water, its partition coefficient, [EHair]/[EHoi]
is found to be lower at 6.0 x 10-6. Account for the difference
between the two values.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7a61b12a-d307-4fed-ba4e-ad2c47a9a398%2F813a9c82-0f98-4515-bf5a-02ccfb768061%2Fhytmgly_processed.png&w=3840&q=75)
Transcribed Image Text:Ethyl heptanoate (EH), a food aroma compound, was added to
water and allowed to come to equilibrium with a known
volume of air and results showed that its partition coefficient,
[EHair]/[EHwater] is equal to 1.8 x 10-2. In the same experiment
with oil in place of water, its partition coefficient, [EHair]/[EHoi]
is found to be lower at 6.0 x 10-6. Account for the difference
between the two values.
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