etermine the ultimate load distribution acting on all beams and girders in the given floor framing below ssume that the supports are simply supported. Compute for the reactions and loads in each beam. Assume nit weight of concrete to be 23.6 kN/m³. Always simplify your load distributions (distributed loads acting or ne same points/locations should be added up). onolithic Floor 3m 2m 2.5m All concrete slabs, t 100 mm All concrete beams, b 250 mm ; h = 500 mm All concrete columns, 300 mm x 300mm uperimposed Loads Floor Finish: C D Ceramic tile 2 inch mortar 5m Ceiling: Wood furring Gypsum board 4 inch thick Mechanical Duct Allowance (MDA) G Frame Partition: Wood, studs with gypsum board h=2.8m

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Determine the ultimate load distribution acting on all beams and girders in the given floor framing below.
Assume that the supports are simply supported. Compute for the reactions and loads in each beam. Assume
unit weight of concrete to be 23.6 kN/m3. Always simplify your load distributions (distributed loads acting on
the same points/locations should be added up).
Monolithic Floor
3m
2m
2.5m
All concrete slabs, t = 100 mm
All concrete beams, b = 250 mm ; h = 500 mm
All concrete columns, 300 mm x 300mm
B
C
Superimposed Loads
Floor Finish:
Ceramic tile 2 inch mortar
5m
Ceiling:
Wood furring
Gypsum board 4 inch thick
Mechanical Duct Allowance (MDA)
G
Frame Partition:
Wood, studs with gypsum board h=2.8m
Utilities: twice the weight of MDA
Exterior Walls
Normal Unit Weight Concrete Masonry/
4 inch thick with plastering on both faces, full grout
height=3m (no interior walls)
ncrete Hollow Blocks, CHB
Live Load
Residential
NOTE: REFER TO NSCP 2015 CHAPTER 2 FOR THE MINIMUM DESIGN LOADS.
USE LRFD LOAD FACTORSS: 1.2 DL + 1.6 LL
Transcribed Image Text:Determine the ultimate load distribution acting on all beams and girders in the given floor framing below. Assume that the supports are simply supported. Compute for the reactions and loads in each beam. Assume unit weight of concrete to be 23.6 kN/m3. Always simplify your load distributions (distributed loads acting on the same points/locations should be added up). Monolithic Floor 3m 2m 2.5m All concrete slabs, t = 100 mm All concrete beams, b = 250 mm ; h = 500 mm All concrete columns, 300 mm x 300mm B C Superimposed Loads Floor Finish: Ceramic tile 2 inch mortar 5m Ceiling: Wood furring Gypsum board 4 inch thick Mechanical Duct Allowance (MDA) G Frame Partition: Wood, studs with gypsum board h=2.8m Utilities: twice the weight of MDA Exterior Walls Normal Unit Weight Concrete Masonry/ 4 inch thick with plastering on both faces, full grout height=3m (no interior walls) ncrete Hollow Blocks, CHB Live Load Residential NOTE: REFER TO NSCP 2015 CHAPTER 2 FOR THE MINIMUM DESIGN LOADS. USE LRFD LOAD FACTORSS: 1.2 DL + 1.6 LL
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