Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
![### Problem Statement
Determine the \([H^+]\), pH, and pOH of a solution with an \([OH^-]\) of \(7.8 \times 10^{-6}\) M at 25 °C.
#### Calculations
1. **[H⁺] Calculation**:
Use the formula: \([H^+] \times [OH^-] = 1.0 \times 10^{-14}\).
2. **pH Calculation**:
Use the formula: \(\text{pH} = -\log[H^+]\).
3. **pOH Calculation**:
Use the formula: \(\text{pOH} = -\log[OH^-]\).
4. **Relationship between pH and pOH**:
\(\text{pH} + \text{pOH} = 14\).
#### Input Fields
- \([H^+]\) = \([\_\_\_\_\_\_\_\_\_\_\_\_]\)
- pH = \([\_\_\_\_\_\_\_\_\_\_\_\_]\)
- pOH = \([\_\_\_\_\_\_\_\_\_\_\_\_]\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4a46be85-81d4-49e6-8ea4-5055a0d2528a%2F06897e2e-d2d4-436b-a68d-79a00258669e%2F3s43cjb_processed.jpeg&w=3840&q=75)
![**Problem Statement**
Determine the \([OH^-]\), pH, and pOH of a solution with a \([H^+]\) of 0.00035 M at 25 °C.
**Analysis Fields**
1. **\[OH^-\] =** [Enter calculated value here]
2. **pH =** [Enter calculated value here]
3. **pOH =** [Enter calculated value here]
**Instructions:**
1. Use the relationship \( [OH^-] \times [H^+] = 1 \times 10^{-14} \) to calculate \([OH^-]\).
2. Calculate pH using the formula: \( \text{pH} = -\log[H^+] \).
3. Use the relation \( \text{pH} + \text{pOH} = 14 \) to find pOH, after determining pH.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4a46be85-81d4-49e6-8ea4-5055a0d2528a%2F06897e2e-d2d4-436b-a68d-79a00258669e%2F3b22kpc_processed.jpeg&w=3840&q=75)
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