decay in the discharging process to half of its maximum (V = Vo/2). This time is the half-life: t1= t1/2. 20.82 ms, 3.977v T1= 1.4 m/s Measure the time it takes for the voltage to decay to one-quarter (V = Vo/4 = (Vo/2)2) of its maximum. This is two half-lives: t2 = 2t1/2. Then divide this time by two to find the half-life (t1/2 = t2/2) 20.2-24.00 = 3.2 T2 = 3.2/2 = 1.6m/sMeasure the time it takes for the voltage to grow to one-eighth (V = Vo/8 = (Vo/2)3) of its This is three half-lives, t3 = 3t1/2. Then divide this time by three to find the half-life, t1/2 = t3/3. 20.8 – 22.28= 1.48m/s T3= 1.48/3 = 0.49 m/sTake the average of the three measured values of the half-life. Estimate the precision of the measurement and state it as {half-life ± precision} 1.4 + 1.6 + 0.49 / 3 = 1.16 half-life +- Precision Estimate the time constant from the average half-life.

Answered: Image /qna-images/answer/4b691de0-7fdb-4f4c-8f5f-c6535bfadd35.jpg

Answered: Estimate the time constant from the…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Concept explainers

Question

decay in the discharging process to half of its maximum (V = V_o/2). This time is the half-life: t1= t_1/2.

20.82 ms, 3.977v

T1= 1.4 m/s

Measure the time it takes for the voltage to decay to one-quarter (V = V_o/4 = (V_o/2)²) of its maximum. This is two half-lives: t2 = 2t_1/2. Then divide this time by two to find the half-life (t_1/2 ₌ t2/2)

20.2-24.00 = 3.2

T2 = 3.2/2 = 1.6m/s

Measure the time it takes for the voltage to grow to one-eighth (V = V_o/8 = (V_o/2)³) of its This is three half-lives, t3 = 3t_1/2. Then divide this time by three to find the half-life, t_1/2 ₌ t3/3.

20.8 – 22.28= 1.48m/s

T3= 1.48/3 = 0.49 m/s

Take the average of the three measured values of the half-life. Estimate the precision of the measurement and state it as {half-life ± precision}

1.4 + 1.6 + 0.49 / 3 = 1.16 half-life +- Precision

Estimate the time constant from the average half-life.

Expert Solution

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions