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Estimate the apparent slope of the plot for myoglobin. myoglobin apparent slope = Estimate the apparent slope in the center of the plot for hemoglobin. hemoglobin apparent slope = What do these apparent slope values suggest about myoglobin and hemoglobin? The apparent slope value for myoglobin suggests The apparent slope value for hemoglobin suggests negative cooperative binding. noncooperative binding. positive cooperative binding.

Estimate the apparent slope of the plot for myoglobin. myoglobin apparent slope = Estimate the apparent slope in the center of the plot for hemoglobin. hemoglobin apparent slope = What do these apparent slope values suggest about myoglobin and hemoglobin? The apparent slope value for myoglobin suggests The apparent slope value for hemoglobin suggests negative cooperative binding. noncooperative binding. positive cooperative binding.

Biochemistry
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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In 1913, Archibald Hill described an alternative formulation for cooperative processes such as the binding of oxygen by hemoglobin by considering the hypothetical equilibrium Hb+ n0₂ Hb(0₂)n 2 Analysis leads to the Hill equation: n p02₂" ( Y log (₁ x x ) = log Y (^_^) log where Y is the fractional saturation. This equation suggests that a plot of log with slope n. Plots for myoglobin and hemoglobin are shown here: 3 2 1 O -1 -2 -3 P50 + n = nlog (pO,) – n log(P5o) Myoglobin (0.25, -0.25) -1 0 1 2 log (pO₂) (3.0, 2.5) 3 4 (^_^) log 3 2 1 O -1 -2 -3 -4 (0, -3.4) -1 0 Y Y versus log (pO₂) should yield a line Hemoglobin (2.1, 2.5) - (0.7, -2.0) (1.9, 1.3) (0.4, -3.5) 1 2 log (pO₂) - (2.4, 2.4) 3 4
Transcribed Image Text:In 1913, Archibald Hill described an alternative formulation for cooperative processes such as the binding of oxygen by hemoglobin by considering the hypothetical equilibrium Hb+ n0₂ Hb(0₂)n 2 Analysis leads to the Hill equation: n p02₂" ( Y log (₁ x x ) = log Y (^_^) log where Y is the fractional saturation. This equation suggests that a plot of log with slope n. Plots for myoglobin and hemoglobin are shown here: 3 2 1 O -1 -2 -3 P50 + n = nlog (pO,) – n log(P5o) Myoglobin (0.25, -0.25) -1 0 1 2 log (pO₂) (3.0, 2.5) 3 4 (^_^) log 3 2 1 O -1 -2 -3 -4 (0, -3.4) -1 0 Y Y versus log (pO₂) should yield a line Hemoglobin (2.1, 2.5) - (0.7, -2.0) (1.9, 1.3) (0.4, -3.5) 1 2 log (pO₂) - (2.4, 2.4) 3 4
Estimate the apparent slope of the plot for myoglobin. myoglobin apparent slope = Estimate the apparent slope in the center of the plot for hemoglobin. hemoglobin apparent slope = What do these apparent slope values suggest about myoglobin and hemoglobin? The apparent slope value for myoglobin suggests The apparent slope value for hemoglobin suggests negative cooperative binding. noncooperative binding. positive cooperative binding.
Transcribed Image Text:Estimate the apparent slope of the plot for myoglobin. myoglobin apparent slope = Estimate the apparent slope in the center of the plot for hemoglobin. hemoglobin apparent slope = What do these apparent slope values suggest about myoglobin and hemoglobin? The apparent slope value for myoglobin suggests The apparent slope value for hemoglobin suggests negative cooperative binding. noncooperative binding. positive cooperative binding.
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