est Baby class by writing a client program which uses an array to store information about 4 babies. That is, each of the four elements of the array must store a Baby object. There should not be an array for for baby names and another array for baby ages. A Baby class object stores the required information about a Baby. So each Baby object will have its own relevant information, and thus each object must be stored in one element of the array. The client program should: a. Enter details for each baby (name and age) and thus populate the Baby array b. Output the details of each baby from the array (name and age) c. Calculate and display the average age of all babies in the array d. Determine whether any two babies in the array are the same. class Baby{ //data members private String name; private int age; //default constructor Baby() { name = "xyz"; age = 3; } //parameterized constructor Baby(String n,int a){ name = n; age = a; } //sets name public void setname(String n){ if(n.isEmpty()) name = "xyz"; else name = n; } //sets age public void setage(int a){ if(!(a>=1 && a<=4)) age = 2; else age = a; } //returns name public String getname(){ return name; } //returns age public int getage(){ return age; } //check if two objects have same name and age public boolean equals(Baby b){ if (age==b.getage() && name.equalsIgnoreCase(b.getname())) return true; else return false; } } public class Main { public static void main(String[] args) { //two objects of type Baby Baby A=new Baby("abcd",3); Baby B= new Baby("abcd",3); //print information of object System.out.println("Name:" + A.getname() + " age:"+ A.getage()); //call equals on obejct A and pass object B to it System.out.println("The two babies are identical? " + A.equals(B)); } }
Test Baby class by writing a client
information about 4 babies. That is, each of the four elements of the array
must store a Baby object.
There should not be an array for for baby names and another array for baby ages.
A Baby class object stores the required information about a Baby. So
each Baby object will have its own relevant information, and thus each
object must be stored in one element of the array.
The client program should:
a. Enter details for each baby (name and age) and thus populate the
Baby array
b. Output the details of each baby from the array (name and age)
c. Calculate and display the average age of all babies in the array
d. Determine whether any two babies in the array are the same.
class Baby{
//data members
private String name;
private int age;
//default constructor
Baby()
{
name = "xyz";
age = 3;
}
//parameterized constructor
Baby(String n,int a){
name = n;
age = a;
}
//sets name
public void setname(String n){
if(n.isEmpty())
name = "xyz";
else
name = n;
}
//sets age
public void setage(int a){
if(!(a>=1 && a<=4))
age = 2;
else
age = a;
}
//returns name
public String getname(){
return name;
}
//returns age
public int getage(){
return age;
}
//check if two objects have same name and age
public boolean equals(Baby b){
if (age==b.getage() && name.equalsIgnoreCase(b.getname()))
return true;
else
return false;
}
}
public class Main
{
public static void main(String[] args) {
//two objects of type Baby
Baby A=new Baby("abcd",3);
Baby B= new Baby("abcd",3);
//print information of object
System.out.println("Name:" + A.getname() + " age:"+ A.getage());
//call equals on obejct A and pass object B to it
System.out.println("The two babies are identical? " + A.equals(B));
}
}
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