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Equipment for measuring concentration of bacteria has standard deviation σ = 0.75 106 bacteria/(ml of fluid). Using the sample mean as an estimate of the concentration of bacteria, how many measurements are required to ensure the margin of error not to exceed 0.5 106 bacteria/ml, with confidence of at least 95%? You may want to use one of the following: qnorm(0.95, lower.tail=FALSE) = -1.644854 qnorm(0.05, lower.tail=FALSE) = 1.644854 qnorm(0.025, lower.tail=FALSE) = 1.959964 09 8 07 O 10

Equipment for measuring concentration of bacteria has standard deviation σ = 0.75 106 bacteria/(ml of fluid). Using the sample mean as an estimate of the concentration of bacteria, how many measurements are required to ensure the margin of error not to exceed 0.5 106 bacteria/ml, with confidence of at least 95%? You may want to use one of the following: qnorm(0.95, lower.tail=FALSE) = -1.644854 qnorm(0.05, lower.tail=FALSE) = 1.644854 qnorm(0.025, lower.tail=FALSE) = 1.959964 09 8 07 O 10

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Equipment for measuring concentration of bacteria has standard deviation σ = 0.75 106 bacteria/(ml of fluid). Using the sample mean as an estimate of the concentration of bacteria, how many measurements are required to ensure the margin of error not to exceed 0.5 106 bacteria/ml, with confidence of at least 95%? You may want to use one of the following: qnorm(0.95, lower.tail=FALSE) = -1.644854 qnorm(0.05, lower.tail=FALSE) = 1.644854 qnorm(0.025, lower.tail=FALSE) = 1.959964 09 8 07 O 10
Transcribed Image Text:Equipment for measuring concentration of bacteria has standard deviation σ = 0.75 106 bacteria/(ml of fluid). Using the sample mean as an estimate of the concentration of bacteria, how many measurements are required to ensure the margin of error not to exceed 0.5 106 bacteria/ml, with confidence of at least 95%? You may want to use one of the following: qnorm(0.95, lower.tail=FALSE) = -1.644854 qnorm(0.05, lower.tail=FALSE) = 1.644854 qnorm(0.025, lower.tail=FALSE) = 1.959964 09 8 07 O 10
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