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2.33 A weight W = 200# is supported by a cable system as shown. Determine all cable forces and the force in the vertical boom BC. CABLE A A W =200# E in 75 Equilibrium Equations: Two-dimensional 2.28 Ra= Rc= 2.29 (change force to 600N) AC= AB= 2.33 CD= AC= DE= BC= Free Body Diagrams 2.34 Ax= Ay=_ Bx= By= 2.36 Ax= Ay= Bx= By= 2.37 (change middle force to 4000 lbs) Ay=_ Dx= Dy=_ 2.38 (change horizontal force to 2 kN) Ax= Ay= Bx= By=_ 2.40 Ay= By= Dx= 32% Bx= Cy= Dy=

2.33 A weight W = 200# is supported by a cable system as shown. Determine all cable forces and the force in the vertical boom BC. CABLE A A W =200# E in 75 Equilibrium Equations: Two-dimensional 2.28 Ra= Rc= 2.29 (change force to 600N) AC= AB= 2.33 CD= AC= DE= BC= Free Body Diagrams 2.34 Ax= Ay=_ Bx= By= 2.36 Ax= Ay= Bx= By= 2.37 (change middle force to 4000 lbs) Ay=_ Dx= Dy=_ 2.38 (change horizontal force to 2 kN) Ax= Ay= Bx= By=_ 2.40 Ay= By= Dx= 32% Bx= Cy= Dy=

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 30RE
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2.33 A weight W = 200# is supported by a cable system as shown. Determine all cable forces and the force in the vertical boom BC. CABLE A A W =200# E in 75
Transcribed Image Text:2.33 A weight W = 200# is supported by a cable system as shown. Determine all cable forces and the force in the vertical boom BC. CABLE A A W =200# E in 75
Equilibrium Equations: Two-dimensional 2.28 Ra= Rc= 2.29 (change force to 600N) AC= AB= 2.33 CD= AC= DE= BC= Free Body Diagrams 2.34 Ax= Ay=_ Bx= By= 2.36 Ax= Ay= Bx= By= 2.37 (change middle force to 4000 lbs) Ay=_ Dx= Dy=_ 2.38 (change horizontal force to 2 kN) Ax= Ay= Bx= By=_ 2.40 Ay= By= Dx= 32% Bx= Cy= Dy=
Transcribed Image Text:Equilibrium Equations: Two-dimensional 2.28 Ra= Rc= 2.29 (change force to 600N) AC= AB= 2.33 CD= AC= DE= BC= Free Body Diagrams 2.34 Ax= Ay=_ Bx= By= 2.36 Ax= Ay= Bx= By= 2.37 (change middle force to 4000 lbs) Ay=_ Dx= Dy=_ 2.38 (change horizontal force to 2 kN) Ax= Ay= Bx= By=_ 2.40 Ay= By= Dx= 32% Bx= Cy= Dy=
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