Equations: ΔΗ-Σ(nΔΗμ)-Σ (n- ΔΗ..s) ΔSΣ (- ΔS,luas) -Σ (n- ΔS,.. m ts) AG = E(n - AGmotucts) – E (n - AGreactan to) AG = AH – TAS Hydrogen peroxide, H2O2, decomposes into water and oxygen gas with an enthalpy (AH) change of -37.77 kJ and an entropy (AS) change of -130.92 JIK. Will this reaction be spontaneous if the H2O2 is kept in a sub-zero refrigerator at -25 °C?
Equations: ΔΗ-Σ(nΔΗμ)-Σ (n- ΔΗ..s) ΔSΣ (- ΔS,luas) -Σ (n- ΔS,.. m ts) AG = E(n - AGmotucts) – E (n - AGreactan to) AG = AH – TAS Hydrogen peroxide, H2O2, decomposes into water and oxygen gas with an enthalpy (AH) change of -37.77 kJ and an entropy (AS) change of -130.92 JIK. Will this reaction be spontaneous if the H2O2 is kept in a sub-zero refrigerator at -25 °C?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Math Short Answer
#### Question 09
**Equations:**
\[
\Delta H = \Sigma (n \cdot \Delta H_{\text{products}}) - \Sigma (n \cdot \Delta H_{\text{reactants}})
\]
\[
\Delta S = \Sigma (n \cdot \Delta S_{\text{products}}) - \Sigma (n \cdot \Delta S_{\text{reactants}})
\]
\[
\Delta G = \Sigma (n \cdot \Delta G_{\text{products}}) - \Sigma (n \cdot \Delta G_{\text{reactants}})
\]
\[
\Delta G = \Delta H - T \Delta S
\]
Hydrogen peroxide, \( \text{H}_2\text{O}_2 \), decomposes into water and oxygen gas with an enthalpy (\( \Delta H \)) change of -37.77 kJ and an entropy (\( \Delta S \)) change of -130.92 J/K. Will this reaction be spontaneous if the \( \text{H}_2\text{O}_2 \) is kept in a sub-zero refrigerator at -25 °C?
**Feedback:**
_ABBEY RICKELMANN:_ You needed to remember to multiply \( \Delta H \) by 1000.
**Score:** 6 / 10
---
#### Question 10
A 25.0 g mold made of an alloy absorbed 250 J of heat as its temperature changed from 25 °C to 78 °C. What is the specific heat of the alloy?
**Score:** 10 / 10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F19694491-1798-4a06-be66-17e405b2da28%2F8fcbb8fe-4d24-48de-901d-4447ded62496%2F9yfa1e_processed.png&w=3840&q=75)
Transcribed Image Text:### Math Short Answer
#### Question 09
**Equations:**
\[
\Delta H = \Sigma (n \cdot \Delta H_{\text{products}}) - \Sigma (n \cdot \Delta H_{\text{reactants}})
\]
\[
\Delta S = \Sigma (n \cdot \Delta S_{\text{products}}) - \Sigma (n \cdot \Delta S_{\text{reactants}})
\]
\[
\Delta G = \Sigma (n \cdot \Delta G_{\text{products}}) - \Sigma (n \cdot \Delta G_{\text{reactants}})
\]
\[
\Delta G = \Delta H - T \Delta S
\]
Hydrogen peroxide, \( \text{H}_2\text{O}_2 \), decomposes into water and oxygen gas with an enthalpy (\( \Delta H \)) change of -37.77 kJ and an entropy (\( \Delta S \)) change of -130.92 J/K. Will this reaction be spontaneous if the \( \text{H}_2\text{O}_2 \) is kept in a sub-zero refrigerator at -25 °C?
**Feedback:**
_ABBEY RICKELMANN:_ You needed to remember to multiply \( \Delta H \) by 1000.
**Score:** 6 / 10
---
#### Question 10
A 25.0 g mold made of an alloy absorbed 250 J of heat as its temperature changed from 25 °C to 78 °C. What is the specific heat of the alloy?
**Score:** 10 / 10
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