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ength ing 1. p = 0.25 n = 300 CL = 95% %3D 2. p = 0.35 n = 320 CL = 90% %3D %3D 3. p = 0.48 n = 210 CL = 92% = 220 CL = 93% n = 41 CL = 99% = 100 CL = 99% 4. p = = 0.38 %3D 5. o = 0.45 6. o = 0. 15 n = 7. o = 0, 25 %3D n = 50 CL = 95% 8. s = 1.35 n = 25 CL = 98% 9. s = 4. 44 = 18 CL 90% n 10. = 3 n = 26 CL 99% %3D

ength ing 1. p = 0.25 n = 300 CL = 95% %3D 2. p = 0.35 n = 320 CL = 90% %3D %3D 3. p = 0.48 n = 210 CL = 92% = 220 CL = 93% n = 41 CL = 99% = 100 CL = 99% 4. p = = 0.38 %3D 5. o = 0.45 6. o = 0. 15 n = 7. o = 0, 25 %3D n = 50 CL = 95% 8. s = 1.35 n = 25 CL = 98% 9. s = 4. 44 = 18 CL 90% n 10. = 3 n = 26 CL 99% %3D

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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DIRECTION . Find the length of the following confidence interval 1. р3D 0.25 n = 300 CL = 95% 2. p = 0.35 = 320 CL = 90% %3D 3. p = 0.48 n = 210 CL = 92% 4. p = 0.38 5. o = 0.45 = 0.15 7. o = 0.25 = 220 CL 93% %3D !! n = 41 CL = 99% 6. 0 = n = 100 CL = 99% = 50 CL 95% n 8. s = 1.35 n = 25 CL 98% %3D 9. s = 4.44 = 18 CL 90% %3D 10. 2. = 3 CL = 99% n = 26
Transcribed Image Text:DIRECTION . Find the length of the following confidence interval 1. р3D 0.25 n = 300 CL = 95% 2. p = 0.35 = 320 CL = 90% %3D 3. p = 0.48 n = 210 CL = 92% 4. p = 0.38 5. o = 0.45 = 0.15 7. o = 0.25 = 220 CL 93% %3D !! n = 41 CL = 99% 6. 0 = n = 100 CL = 99% = 50 CL 95% n 8. s = 1.35 n = 25 CL 98% %3D 9. s = 4.44 = 18 CL 90% %3D 10. 2. = 3 CL = 99% n = 26
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