4. Find the value of x and the measure of ZDEG. (8x + 3)° 1 MLDEG == (mDG – mDF) (31x- 4) 190 ー=X X = M2DEG = (8x + 3) MLDEG = [8(_) + 3] MLDEG = (_+3) %3D M2DEG = . x is and mLDEG =
4. Find the value of x and the measure of ZDEG. (8x + 3)° 1 MLDEG == (mDG – mDF) (31x- 4) 190 ー=X X = M2DEG = (8x + 3) MLDEG = [8(_) + 3] MLDEG = (_+3) %3D M2DEG = . x is and mLDEG =
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Question
![4. Find the value of x and the measure of ZDEG.
(8x + 3)°
(mDG – mDF)
2
M2DEG =
(31x- 4))
190
X =
X =
x = -
X =
M2DEG =
(8x + 3)
MLDEG = [8(_)+ 3]
MLDEG = (_+3)
%3D
M2DEG =
.. x is
and mzDEG =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5cbf5a1e-6c86-41cb-8eae-656678184754%2F17605b31-e7cb-47ae-b9b2-4b14148d92da%2Fswr693_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4. Find the value of x and the measure of ZDEG.
(8x + 3)°
(mDG – mDF)
2
M2DEG =
(31x- 4))
190
X =
X =
x = -
X =
M2DEG =
(8x + 3)
MLDEG = [8(_)+ 3]
MLDEG = (_+3)
%3D
M2DEG =
.. x is
and mzDEG =
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