Energetically FavoredHomework. UnansweredWhich of these chemical processes is energetically favored in the forward direction? (select all that apply)Multiple answers: Multiple answers are accepted for this questionSelect one or more answers and submit. For keyboard navigation, SHOW MORECl2(g) + H,0(1)HOCI(aq) + HCl(aq)ab.NH,CI(aq) + NH,C((aq) = 2NH3(aq) + Cl;(g)Co,(g) + H2(g) = H,0(1) + CO(g)Unanswered 5 attempts leftSubmit

Introduction: ∆G =∆H -T∆S ∆G should be negative for proceeding a reaction in a particular…

Energetically Favored Homework Unanswered Which of these chemical processes is energetically favored in the forward direction? (select all that apply) Multiple answers: Multiple answers are accepted for this quesMion Select one or more answers and submit. For keyboard navigation SHOW MORE Cl(g) + H,0(1) = HOCI(aq) + HCI(aq) a NH,CI(aq) + NH,C((aq) = 2NH,(aq) + Cl,(g) Co (g) + H2(g) =H,0(1) + CO(g)

Energetically Favored Homework Unanswered Which of these chemical processes is energetically favored in the forward direction? (select all that apply) Multiple answers: Multiple answers are accepted for this quesMion Select one or more answers and submit. For keyboard navigation SHOW MORE Cl(g) + H,0(1) = HOCI(aq) + HCI(aq) a NH,CI(aq) + NH,C((aq) = 2NH,(aq) + Cl,(g) Co (g) + H2(g) =H,0(1) + CO(g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider the molar enthalpy change for this neutralization reaction: HCl(aq)+NaOH(aq)⟶NaCl(aq)+H2O(l)ΔH∘=−57.3kJ/mol We mixed 30 mL of 1.0 M HCl with 70 mL of 1.0 M NaOH. What is the theoretical value for the temperature increase? Express your answer in ∘C.
Determine ASa for H2(g) + I,(8) 5 2HI(g) given the following information: Substance S° (J/mol · K) H2(g) 130.58 I2(3) 116.73 HI(g) 206.3 O -41.10 J/K O -165.29 J/K +398.75 J/K O +165.29 J/K O +41.10 J/K
A metal oxide MO was reduced with carbon, as follows. 2 MO(s) + C(s) → 2 M(s) + CO2(g) The reaction of 0.790 mol of MO(s) with excess carbon released 227 kJ of heat at constant pressure. What is ΔrH (in kJ/mol) for this reaction? Round your answer to the tenths (0.1) place.
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Using Hess's law, what is AHf rxn for the following reaction? NO(G) + O(g) – NO2(9) NO(g) + O3(9) – NO2(9) +O2(9) AH xn = -198.8 kJ/mol Og(9) – 3/2 02(9) AHrxn = -142.2 kJ/mol 02(9) → 20(9) AH Prxn = +498.8 kJ/mol -839.8 kJ/mol -306.0 kJ/mol 394.9 kJ/mol 157.9 kJ/mol O 442.3 kJ/mol QUESTION 8 Octane (C3H18) undergoes combustion according to the following thermochemical equation. 2C8H18() + 2502(g) – 16CO2(g) + 18H20() AH°rxn = -1.0940 x 104KJ/mol What is the standard enthalpy of formation of liquid octane? AH°{(CO2(g)) = -393.5 kJ/mol and AH°F{H2O(1)) = -285.8 kJ/mol 495 kl/mol O -250 kJ/mol -495 kJ/mol -10,940. kJ/mol -2188 kJ/mol
Using the equation labels in the laboratory procedure, which of the following illustrates the correct calculation for ΔH4? (1) C(s) + 1/2O2(g) → CO(g) ∆H1 = ? (2) C(s) + O2(g) → CO2(g) ∆H2 = -395.7 kJ/mol (3) CO(g) + 1/2O2(g) → CO2(g) ∆H3 = -283.2 kJ/mol Summing reactions appropriately to determine ∆H1: C(s) + O2(g) → CO2(g) ∆H2 = -395.7 kJ/mol (Reaction 2) CO2(g) → CO(g) + 1/2O2(g) (-∆H3) = 283.2 kJ/mol (reverse of 3) Sum: C(s) + 1/2O2 → CO(g) -395.7 + 283.2 = -112.5 kJ/mol Determination of the Enthalpy of Sublimation and Decomposition of NH4Cl In the laboratory experiment today, the heat of sublimation and decomposition of NH4Cl(s) will be determined. The process is represented by Equation 4. (4) NH4Cl(s) → NH3(g) + HCl(g) ∆H4 = ? Solid ammonium chloride sublimes (i.e., changes from a solid to a gas) at 340oC and decomposes to gaseous ammonia and hydrogen chloride. ∆H4 is obtained via mathematical manipulation of four equations and the enthalpy changes corresponding to…
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D= Delta symbol Using Hess’s law (the indirect method) show how you can combine the following chemical reactions to determine the DHrxn for the following reaction. Zn (s) + 1/8 S8 (s) + 2 O2 (g) --> ZnSO4 (s) Goal: Determine DHrxn? Using the reactions below Zn (s) + 1/8 S8 (s) --> ZnS (s) DHrxn=A 2 ZnS (s) + 3 O2 (g) --> 2 ZnO (s) + 2 SO2 (g) DHrxn=B 2 SO2 (g) + O2 (g) --> 2 SO3 (g) DHrxn=C ZnSO4 --> ZnO (s) + SO3 (g) DHrxn=D
10:11 ull 5G Question 14 of 15 Submit What is the change in enthalpy in kilojoules when 3.24 g of CH;OH gas is completely reacted according to the following reaction? CH;OH(g) → 2 CHa(g) + O2(g) AH = 252.8 kJ X STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 7.80 x 10-4 2 16.05 mol O2 6.022 x 1023 12.8 J 32.00 0.101 mol CH,OH 1000 3.24 mol CH. 0.001 252.8 g CH,OH 32.05 4.00 x 10-4 g CH. 1 25.6 kJ Tap here or pull up for additional resources
Use the following information to answer the question: What is the ΔH (in kJ/mol) for the following reaction? (Show work) CS2(l) + 3 O2(g) → CO2(g) + 2 SO2(g) Given: C(s) + O2(g) → CO2(g); ΔHf = -393.5 kJ/mol S(s) + O2(g) → SO2(g); ΔHf = -296.8 kJ/mol C(s) + 2 S(s) → CS2(l); ΔHf = 87.9 kJ/mol