Encrypt the message " HALT " by translating the letters into numbers (via A = 0, B = 1, C = 2, D = 3, E = 4, F = 5, G = 6, H = 7, I = 8, J = 9, K = 10, L = 11, M = 12, N = 13, 0 = 14, P = 15, Q = 16, R = 17, S = 18, T = 19,U = 20, V = 21, W = 22, X = 23, Y = 24, Z = 25) %3D %3D and then applying the encryption function given, and then translating the numbers back into letters. (a) f(p) = (p+ 5) mod 26 %3D (b) †(p) = (p + 10) mod 26 (c) f(p) = (p+ 7) mod 26
Encrypt the message " HALT " by translating the letters into numbers (via A = 0, B = 1, C = 2, D = 3, E = 4, F = 5, G = 6, H = 7, I = 8, J = 9, K = 10, L = 11, M = 12, N = 13, 0 = 14, P = 15, Q = 16, R = 17, S = 18, T = 19,U = 20, V = 21, W = 22, X = 23, Y = 24, Z = 25) %3D %3D and then applying the encryption function given, and then translating the numbers back into letters. (a) f(p) = (p+ 5) mod 26 %3D (b) †(p) = (p + 10) mod 26 (c) f(p) = (p+ 7) mod 26
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Transcribed Image Text:Encrypt the message " HALT " by translating the letters into numbers
(via A = 0, B = 1, C = 2, D = 3, E = 4, F = 5, G = 6, H = 7, I = 8,
J = 9, K = 10, L = 11, M = 12, N = 13, O = 14, P = 15, Q = 16, R = 17,
S = 18, T = 19, U = 20, V = 21, W = 22, X = 23, Y = 24, Z = 25 )
%3D
and then applying the encryption function given, and then translating the numbers
back into letters.
(a) f(p) = (p+ 5) mod 26
(b) †(p) = (p + 10) mod 26
(c) f(p)
(р + 7) mod 26
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