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- Problem 7. A personnel manager has found that, historically, the scores on aptitude tests given to applicants for entry-level positions follow a normal distribution with standard deviation 20.3 points. A random sample of 16 test scores from the current group of applicants had a mean score of 68.28 points. Based on these sample results, a statistician found for the population mean a confidence interval extending from 58.4853 to 78.0747 points. Find the confidence level (as a value between zero and one) of this interval.ANSWER IN T-DISTRIBUTION. A group of mathematics teachers wants to estimate the average computational skills of the students in senior high school. the standard deviation from the previous study is 5. how large must the sample be selected if they want to have 95% confidence of finding whether the true mean differs from the sample mean by 3.34% of CSU students participate in the Statistics Games while they attend CSU. You take a random sample of 40 students. You want to determine the probability that more than 15 of them have participated in the Statistics games. Since the conditions are met, you decide to use the Normal model to find your answer. What is the mean and standard deviation of the sampling distribution?
- esc Introduction A chain of restaurants has historically had a mean wait time of 9 minutes for its customers. Recently, the restaurant added several very popular dishes back to their menu. Due to this, the manager suspects the wait time, μ, has increased. He takes a random sample of 44 customers. The mean wait time for the sample is 9.6 minutes. Assume the population standard deviation for the wait times is known to be 3.3 minutes. Can the manager conclude that the mean wait time is now greater than 9 minutes? Perform a hypothesis test, using the 0.05 level of significance. (a) State the null hypothesis Ho and the alternative hypothesis H₁. Ho: O H₁:0 (b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. The value of the test statistic is given by Standard Normal Distribution Step 1: Select one-tailed or two-tailed. O One-tailed O Two-tailed Explanation μ Check □<口 X X OSO 020 0=0 x-H √n • The p-value is the area under the curve to the right…A basketball player wants to know if they make more than 75% of the penalty shots that they take. What is the appropriate test statistic for this scenario? one sample t-test two independent samples t-test two related samples t-test ANOVAIn a t-test for paired samples, the one value that compares, for each person, her or his two measurements is called the . Difference score Deviation score Standard deviation Standard difference
- 1J,000 Source: Chronicle of Higher Education. 17. Medical Operations The director of a medical hospital feels that her surgeons perform fewer operations per year than the national average of 211. She selected a random sample of 15 surgeons and found that the mean number of operations they performed was 208.8. The standard deviation of the sample was 3.8. Is there enough evidence to support the director's feelings at a= 0.10? Would the null hypothesis be rejected at a = 0.01? 18. Cell Phone Call Lengths The average local cell phone call length was reported to be 2.27 minutes. A random sample of 20 phone calls showed an average of 2.98 minutes in length with a standard deviation of 0.98 minute. At a = 0.05, can it be concluded that the average differs from the population average? %3D World Almanac.A successful basketball player has a height of 6 feet 11 inches, or 211 cm. Based on statistics from a data set, his height converts to the z score of 5.17. How many standard deviations is his height above the mean?You have a normal population with a mean of 1000 and a standard deviation of 100.Determine the scores associated with the following percentiles: 50% 45% 95% 5% 77%
- A population has a mean u =78 and a standard deviation o = 24. Find the mean and standard deviation of a sampling distribution of sample means with sample size n = 36. H; =(Simplify your answer.) (Simplify your answer.)Provide an appropriate response.The scores from a state standardized test have a bell-shaped distribution with a mean of 100 and a standard deviation of 15. Use the Empirical Rule to find the percentage of students with scores between 70 and 130. Group of answer choices 95% 68% 99.7% 100%Plzz explain. Ty