ement. Answer number

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Answer the blank in the statement. Answer number 3 only. 

Supply the missing parts.
Given: AC = BC
CO bisects ZACB
Prove: AACO = ABCO
Proof: Since, AC = BC, CO bisects LACB, Hence ACO = LBCO by the
Also 2.
by reflexive
property. Thus, We have AC = BC, LACO e ZBCO, CO = CO,
then AACO AHCO by 3.
Transcribed Image Text:Supply the missing parts. Given: AC = BC CO bisects ZACB Prove: AACO = ABCO Proof: Since, AC = BC, CO bisects LACB, Hence ACO = LBCO by the Also 2. by reflexive property. Thus, We have AC = BC, LACO e ZBCO, CO = CO, then AACO AHCO by 3.
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