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Embryo Gene 1: R Red (or purple) aleurone, dominant Colorless aleurone, recessive Gene 2: Colorless, aleurone color inhibitor Aleurone color when in the presence of color alleles Colorless aleurone layer (even in presence of R_) CC or Cc CC Gene 3: Y_ Yellow endosperm(visible when aleurone colorless) white endosperm (visible when aleurone colorless) For each of the three ears: 1. Make a Punnett square to determine all of the genotypes in the F2 generation. 2. Predict the color exhibited by each genotype based on the rules for kernel color inheritance. 3. Develop a hypothesis for the phenotypic ratio expected in each cross. Without removing the kemels, count the kernels exhibiting each phenotype for ~5-6 rows, >200 kernels. 4.

Embryo Gene 1: R Red (or purple) aleurone, dominant Colorless aleurone, recessive Gene 2: Colorless, aleurone color inhibitor Aleurone color when in the presence of color alleles Colorless aleurone layer (even in presence of R_) CC or Cc CC Gene 3: Y_ Yellow endosperm(visible when aleurone colorless) white endosperm (visible when aleurone colorless) For each of the three ears: 1. Make a Punnett square to determine all of the genotypes in the F2 generation. 2. Predict the color exhibited by each genotype based on the rules for kernel color inheritance. 3. Develop a hypothesis for the phenotypic ratio expected in each cross. Without removing the kemels, count the kernels exhibiting each phenotype for ~5-6 rows, >200 kernels. 4.

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Save On Maize... • Upload Pending Olatunde , Bisola Home Insert Draw Design Layout References Mailings Review View Help Garamond v 12 BIU ab x, x A 三三三v 田、 T A P Av Aav A^ A Styles Editing Dictate Editor Reuse Files Font Paragraph N Styles Voice Editor Reuse Files Embryo Gene 1: R Red (or purple) aleurone, dominant Colorless aleurone, recessive Colorless, aleurone color inhibitor Aleurone color when in the presence of color alleles Colorless aleurone layer (even in presence of R_) Gene 2: CC or Ct CC Yellow endosperm(visible when aleurone colorless) white endosperm (visible when aleurone colorless) Gene 3: Y_ For each of the three ears: 1. Make a Punnett square to determine all of the genotypes in the F2 generation. 2. Predict the color exhibited by each genotype based on the rules for kernel color inheritance. 3. Develop a hypothesis for the phenotypic ratio expected in each cros. 4. Without removing the kermels, count the kernels exhibiting each phenotype for ~5-6 rows, >200 kemels. 5. Perform a Chi-square to test your hypothesis. 6. Once detemine a hypothesis that is not rejected by the Chi-square test (See Table 2 for Chi-square you D, Focus Text Predictions: On of 8 1343 words X English (United States) W 18°F a acer F
Transcribed Image Text:Save On Maize... • Upload Pending Olatunde , Bisola Home Insert Draw Design Layout References Mailings Review View Help Garamond v 12 BIU ab x, x A 三三三v 田、 T A P Av Aav A^ A Styles Editing Dictate Editor Reuse Files Font Paragraph N Styles Voice Editor Reuse Files Embryo Gene 1: R Red (or purple) aleurone, dominant Colorless aleurone, recessive Colorless, aleurone color inhibitor Aleurone color when in the presence of color alleles Colorless aleurone layer (even in presence of R_) Gene 2: CC or Ct CC Yellow endosperm(visible when aleurone colorless) white endosperm (visible when aleurone colorless) Gene 3: Y_ For each of the three ears: 1. Make a Punnett square to determine all of the genotypes in the F2 generation. 2. Predict the color exhibited by each genotype based on the rules for kernel color inheritance. 3. Develop a hypothesis for the phenotypic ratio expected in each cros. 4. Without removing the kermels, count the kernels exhibiting each phenotype for ~5-6 rows, >200 kemels. 5. Perform a Chi-square to test your hypothesis. 6. Once detemine a hypothesis that is not rejected by the Chi-square test (See Table 2 for Chi-square you D, Focus Text Predictions: On of 8 1343 words X English (United States) W 18°F a acer F
Maize... • Upload Pending Olatunde , Bisola On me Insert Draw Design Layout References Mailings Review View Help Table Design Layout A Garamond v 12 BIU ab x, x A Styles Editing Dictate Editor Reuse A A Aav 会 T Files • Aav A A Font Paragraph N Styles Voice Editor Reuse Files Yellow:Purple Punnett square: in each cell indicate the and the predicted color. genotype Chi-square test of hypothesis: formulate a hypothesis, count the kernels, test the hypothesis. Expected number (O-E) /E Observed O-E (O-E) Phenotypes number Yellow 161 Purple 39 13 words E English (United States) Text Predictions: On D. Focus 18°F 日i A acer 07 12 lı 17
Transcribed Image Text:Maize... • Upload Pending Olatunde , Bisola On me Insert Draw Design Layout References Mailings Review View Help Table Design Layout A Garamond v 12 BIU ab x, x A Styles Editing Dictate Editor Reuse A A Aav 会 T Files • Aav A A Font Paragraph N Styles Voice Editor Reuse Files Yellow:Purple Punnett square: in each cell indicate the and the predicted color. genotype Chi-square test of hypothesis: formulate a hypothesis, count the kernels, test the hypothesis. Expected number (O-E) /E Observed O-E (O-E) Phenotypes number Yellow 161 Purple 39 13 words E English (United States) Text Predictions: On D. Focus 18°F 日i A acer 07 12 lı 17
Expert Solution
Step 1

Biology homework question answer, step 1, image 1 

1. For answer 1 determine all the genotype in F2 generation in this figure. 

2. Predict the color exhibit by each genotype? 

For gene 1:

3:1   (Phenotype ratio,   3 are red aleurone and 1 is colorless). 

1:2:1 ( Genotype ratio, 1 is dominant red aleurone, 2 Red aleurone and 1 is recessive colourless). 

 

For gene 3:

3:1( phenotype ratio, 3 are Yellow and 1 is white). 

1:2:1 (Genotype ratio,  1 is dominant yellow, 2 Yellow and 1 is recessive White). 

 

 

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