em101 A app.101edu.co Word 2 Resource Library - Dashboard wco Writing Centers at. O 11-0218 NCI Theor. 101 Chem101 E Reading list Question 3 of 11 Submit A Solution of citric acid (A3CaĦSO) With a known concentratlon of 0.200 | M H:C&HsO7 is titrated with a 0.750 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 25.0 mL H:C&HsO, according to the following balanced chemical equation: H:CcHsO, + 3 NaOH – Na:C&HsO, + 3 H:0 ARTING AMOUNT ADO FACTOR ANSWER RESET *( ) 0.020 0.750 11.25 15.0 6,67 2.22 25.0 3 1000 20.0 2 0.001 1 0.200 2.00 x 104 M NaOH mL NaOH mol H.CcHsO7 M H.CcHsO, H,CcHsO, 1:34 PM O Type here to search 46°F 2/27/2022

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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101 Chem101
+
A app.101edu.co
E Apps
e Resource Library -.
11-0218 NCI Theor.
101 Chem101
E Reading list
Word
Dashboard
wco Writing Centers at.
Question 3 of 11
Submit
A Solution of citric acid (HSCGHSO7) With a known concentration of0.200 | M H3C$H$O7
is titrated with a 0.750 M NAOH solution. How many ml of NaOH are required to
reach the third equivalence point with a starting volume of 25.0 mL HsCcHsO,
according to the following balanced chemical equation:
H:C&H;O, +
3
NaOH → Na:C&H:O, +
3
H2O
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
0.020
0.750
11.25
15.0
6.67
2.22
25.0
3
1000
20.0
2
0.001
1
0.200
2.00 x 104
M NaOH
mL NaOH
mol H:C&HSO,
M H:CcHsO7
g HsC&H:O7
L HsC&HsO,
1:34 PM
P Type here to search
46°F
2/27/2022
+
Transcribed Image Text:101 Chem101 + A app.101edu.co E Apps e Resource Library -. 11-0218 NCI Theor. 101 Chem101 E Reading list Word Dashboard wco Writing Centers at. Question 3 of 11 Submit A Solution of citric acid (HSCGHSO7) With a known concentration of0.200 | M H3C$H$O7 is titrated with a 0.750 M NAOH solution. How many ml of NaOH are required to reach the third equivalence point with a starting volume of 25.0 mL HsCcHsO, according to the following balanced chemical equation: H:C&H;O, + 3 NaOH → Na:C&H:O, + 3 H2O STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 0.020 0.750 11.25 15.0 6.67 2.22 25.0 3 1000 20.0 2 0.001 1 0.200 2.00 x 104 M NaOH mL NaOH mol H:C&HSO, M H:CcHsO7 g HsC&H:O7 L HsC&HsO, 1:34 PM P Type here to search 46°F 2/27/2022 +
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