E12P6 Problem 6: While preparing a laboratory experiment on capacitors, you connect an ɛ = 4.5V DC power supply to fully charge an old capacitor that is marked C = 330 µF. Your lab assistanthooks up the circuit as shown below. When the switch S is at point a, the capacitor is connected to thepower supply. When the switch S is at point b, the capacitor is disconnected from the power supplyand connected to a voltmeter, V. The voltmeter has an internal resistance R = 10.0 M2.Part (b) Calculate the charge on the capacitor (in Coulombs) when it is fully charged by the power supply.Part (c) After the capacitor is fully charged, you switch the switch to position b at time t = 0 seconds. The voltmeter initially reads 4.5 V. After howmuch elapsed time (in seconds) would you expect the voltmeter to read 1/2 its initial value?1/2 =Part (d) When you actually move the switch to point b, the voltmeter shows it only takes 1000.0 s for the voltage to drop to half its initial value.Which of the following are possible explanations of the observed behavior of this circuit? Select all that apply.OThe capacitor has been physically damaged, effectively bringing the plates closertogether.O The internal resistance of the volt-meter is significantly lower than 10 MQ.O The dielectric in the capacitor has degraded over time, decreasing the effectivecapacitance of the capacitor.OThe internal resistance of the power supply is acting in series with the capacitor,decreasing the overall resistance of the circuit.O The internal resistance of the power supply is acting in parallel with the capacitor,decreasing the overall resistance of the circuit.

The potential of DC power supply, ε=4.5 VCapacitance, C = 330 μFThe internal resistance of a…

em 6: While preparing a laboratory experiment on capacitors, you connect an ɛ = 4.5 upply to fully charge an old capacitor that is marked C = 330 µF. Your lab assistant ircuit as shown below. When the switch S is at point a, the capacitor is connected to the When the switch S is at point b, the capacitor is disconnected from the power supply to a voltmeter, V. The voltmeter has an internal resistance R = 10.0 M2. a IS E ) Calculate the charge on the capacitor (in Coulombs) when it is fully charged by the power supply. rt (c) After the capacitor is fully charged, you switch the switch to position b at time t = 0 seconds. The voltmeter initially reads 4.5 V. After how ime (in seconds) would you expect the voltmeter to read 1/2 its initial value? rt (d) When you actually move the switch to point b, the voltmeter shows it only takes 1000.0 s for the voltage to drop to half its initial value. ollowing are possible explanations of the observed behavior of this circuit? Select all that apply. OThe capacitor has been physically damaged, effectively bringing the plates closer together. OThe internal resistance of the volt-meter is significantly lower than 10 MQ. OTH dielectric in the capacitor has degraded over time, decreasing the effective capacitance of the capacitor. OThe internal resistance of the power supply is acting in series with the capacitor, decreasing the overall resistance of the circuit. OThe internal resistance of the power supply is acting in parallel with the capacitor, decreasing the overall resistance of the circuit.

em 6: While preparing a laboratory experiment on capacitors, you connect an ɛ = 4.5 upply to fully charge an old capacitor that is marked C = 330 µF. Your lab assistant ircuit as shown below. When the switch S is at point a, the capacitor is connected to the When the switch S is at point b, the capacitor is disconnected from the power supply to a voltmeter, V. The voltmeter has an internal resistance R = 10.0 M2. a IS E ) Calculate the charge on the capacitor (in Coulombs) when it is fully charged by the power supply. rt (c) After the capacitor is fully charged, you switch the switch to position b at time t = 0 seconds. The voltmeter initially reads 4.5 V. After how ime (in seconds) would you expect the voltmeter to read 1/2 its initial value? rt (d) When you actually move the switch to point b, the voltmeter shows it only takes 1000.0 s for the voltage to drop to half its initial value. ollowing are possible explanations of the observed behavior of this circuit? Select all that apply. OThe capacitor has been physically damaged, effectively bringing the plates closer together. OThe internal resistance of the volt-meter is significantly lower than 10 MQ. OTH dielectric in the capacitor has degraded over time, decreasing the effective capacitance of the capacitor. OThe internal resistance of the power supply is acting in series with the capacitor, decreasing the overall resistance of the circuit. OThe internal resistance of the power supply is acting in parallel with the capacitor, decreasing the overall resistance of the circuit.