A spring within a spring launcher is compressed a distance, x, and locked into position by a pin at point P. A spherical ball M is placed onto the compressed spring. When the pin is removed, the spring accelerates the ball upwards until the ball then reaches some maximum height above the spring, HM. Assume the compression of the spring is small in comparison to the maximum height reached by the launched ball. The ball is then replaced by a ball with a quarter of the mass, M. The same spring is 4 compressed the same distance, x, and the new ball is launched. HM In terms of HM, determine the maximum height reached by the lighter ball.

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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A spring within a spring launcher is compressed
a distance, x, and locked into position by a pin
at point P. A spherical ball M is placed onto the
compressed spring. When the pin is removed,
the spring accelerates the ball upwards until the
ball then reaches some maximum height above
the spring, HM. Assume the compression of the
spring is small in comparison to the maximum
height reached by the launched ball.
The ball is then replaced by a ball with a quarter
1
of the mass, M. The same spring is
4
compressed the same distance, x, and the new
ball is launched.
HM
In terms of HM, determine the maximum
height reached by the lighter ball.
Transcribed Image Text:A spring within a spring launcher is compressed a distance, x, and locked into position by a pin at point P. A spherical ball M is placed onto the compressed spring. When the pin is removed, the spring accelerates the ball upwards until the ball then reaches some maximum height above the spring, HM. Assume the compression of the spring is small in comparison to the maximum height reached by the launched ball. The ball is then replaced by a ball with a quarter 1 of the mass, M. The same spring is 4 compressed the same distance, x, and the new ball is launched. HM In terms of HM, determine the maximum height reached by the lighter ball.
Choose 1 answer:
A
B
C
D
1
4
HM
HM
2HM
4HM
Transcribed Image Text:Choose 1 answer: A B C D 1 4 HM HM 2HM 4HM
Expert Solution
Step 1

Concept:- Conservation of energy. 

Energy stored in the spring will be converted into potential energy of ball. 

Spring stored  energy = 1/2 (K) × x^2. 

Where K = spring constant. 

X = compression in the spring. 

Potential energy at height H from ground is equal to product of M, acceleration due to gravity(g)  and height above ground (H). 

Potential energy = MgH. ( You can take any refrence point as zero potential energy). 

 

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