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em 2.4 and Eqs. (2.20) and (2.23) 2.6 A liquid is flowing through a vertical tube 0.3 m long and 2.5 mm in 1.D. The densiy of the liquid is 1260 kg m and the mass flow rate is 3.8 x 10 kg s'. a) What is the viscosity in N s m2? b) Check on the validity of your results.

em 2.4 and Eqs. (2.20) and (2.23) 2.6 A liquid is flowing through a vertical tube 0.3 m long and 2.5 mm in 1.D. The densiy of the liquid is 1260 kg m and the mass flow rate is 3.8 x 10 kg s'. a) What is the viscosity in N s m2? b) Check on the validity of your results.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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b) the volume flow rate. ly distribution, direction of graves Compare your expressions with the results of Problem 2.4 and Eqs. (2.20) and (2.23) 2.6 A liquid is flowing through a vertical tube 0.3 m long and 2.5 mm in L.D. The deniry of the liquid is 1260 kg m and the mass flow rate is 3.8 x 10 kg s. a) What is the viscosity in Ns m2? b) Check on the validity of your results. 2.7 Water (viscosity 103Ns m2) flows parallel to a flat horizontal surface. The velocity profile at x = x, is given by U = 6 sin y with v, in m s' and y as distance from surface in mm. ト > 11 4 72 (81/652) /2
Transcribed Image Text:b) the volume flow rate. ly distribution, direction of graves Compare your expressions with the results of Problem 2.4 and Eqs. (2.20) and (2.23) 2.6 A liquid is flowing through a vertical tube 0.3 m long and 2.5 mm in L.D. The deniry of the liquid is 1260 kg m and the mass flow rate is 3.8 x 10 kg s. a) What is the viscosity in Ns m2? b) Check on the validity of your results. 2.7 Water (viscosity 103Ns m2) flows parallel to a flat horizontal surface. The velocity profile at x = x, is given by U = 6 sin y with v, in m s' and y as distance from surface in mm. ト > 11 4 72 (81/652) /2
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