Eliana wants to estimate the number of out of state visitors at a national park. She surveys 200 visitors and finds that 83 of them are from out of state.  Identify the values needed to calculate a confidence interval at the 90% confidence level. Then find the confidence interval.   z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576   Use the table of common z-scores above. Round the final answer to three decimal places. Provide your answer below:   p′= ​  σp′​ = ​  zα/2​​ = ​  (    ,     )

Q: A baseball prospect has hit in 25 out of his first 77 at-bats. Compute a 88% confidence interval for…

A: We have given that x = 25 n = 77 The sample proportion isp̂ = x/n = 25/77 =  0.3247 Confidence level…

Q: Determine the specified confidence interval. It has been estimated, with 90% confidence, the…

A: Given information Proportions of Americans who go out for shopping on Black Friday

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A:

Q: Give the endpoints of the 90% confidence interval for the true population proportion of fruit flies…

A: Sample size is given by n = 500 And number of flies with gene, X = 200 At 90% confidence level, the…

Q: Refer to the accompanying data display that results from a sample of airport data speeds in Mbps.…

A: Given: 95% confidence interval = (13.046, 22.15)

Q: How to find the bounds of the confidence interval. The data is…

A: The sums are, x y x2 xy 25 16.9 625 422.5 27.75 17.6 770.0625 488.4 26.75 17.3 715.5625…

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: Given: Let n represents the number of parents of children surveyed; that is; n=1035. Let p^…

Q: The maker of a cell phone screen protector would like to estimate the proportion of customers who…

A: We have given that  Sample size n =200 96% confidence interval.  (0.15 ,0.28)

Q: Enter the values of the sample size, the point estimate of the populate (Choose the correct critical…

A: a) The sample size is 21+39 =60   b) The point estimate is   P=x/n   = 0.35

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A:

Q: 85 students at a college were asked whether they had completed their required English 101 course,…

A:

Q: Use the accompanying paired data consisting of registered boats (tens of thousands) and manatee…

A: Use EXCEL to determine the regression equation. EXCEL procedure: Go to EXCEL Go to Data>Data…

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: No of parents surveyed n = 1091 Point estimate p-hat = 0.74 Margin of error E = ± 0.04

Q: find the point estimate for the mean and the margin of error. Give your answers precise to two…

A: Given Data Lower limit = 1.97 upper limit = 2.93

Q: In an effort to determine the percent of Portland residents that regularly bike to work, 500…

A: Solution: From the given information, p-hat = 0.35 and margin of error is ±3%.

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: Given info: In a survey of 1002 adults in a country, 79% said being able to speak the language is at…

Q: You want to know about the difference in the percentage of men who get sick when exposed to H1N1 and…

A: Given data: For men: n1 = 150      x1 = 20 For Women: n2 = 200       x2 = 15 Confidence level = 95%…

Q: A random sample of 318 students from a large college was asked if they plan to visit family during…

A: The CI is given to be (0.78, 0.98). point estimate is the midpoint of the interval. Let Margin of…

Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120   significance level =…

Q: you plan to dive to san antonio from college station to visit your friend lupita. that friend is…

A: The summary of statistics is, The degree of freedom is,

Q: The CEO of a company wants to estimate the percent of employees that use company computers to go on…

A: Given, The sample proportion is, Critical value: Using z-table, the z-critical value at the given…

Q: Do pregnant women give birth the week of their due date? A study claims that 33% of the population…

A: Sample size =36+44=80 Proportion of gave birth the week of due date=0.45  We have to find a..Sample…

Q: Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying…

A: Given n=29 x=3

Q: A survey conducted by Sallie Mae and Gallup of 1250 respondents found that 875 students paid for…

A: Solution: Given information: n= 1250 Sample size of respondentsx= 875 students paid for their…

Q: The drug OxyContin is used to treat pain, but it is dangerous because it is addictive and can be…

A: Given,n=278x=76p^=xnp^=76278=0.2731-p^=1-0.273=0.727α=1-0.90=0.1α2=0.05Z0.05=1.645  (from Z-table)

Q: Suppose a random sample of 50 basketball players showed the average height to be 78 inches. Also,…

A: From the provided information, Population standard deviation (σ) = 1.5 Sample mean (x̄) = 78 Sample…

Q: We wish to give a 99% confidence interval for the fraction of fruit flies which possess a certain…

A: According to the given information in this question We need to calculate 99% confidence interval of…

Q: A drug is used to help prevent blood clots in certain patients. In clinical trials, among 4918…

A: The number of patients who suffered adverse reactions is 163 in the sample of 4918 patients.…

Q: se the sample data and confidence level given below to complete parts​ (a) through​ (d).   A drug is…

A: given data, x=118n=4409p^=xn  =1184409   =0.0268CI=0.90

Q: Alaxicompany is tying to decode whether to purchase brand A or brand B tres fo is fe f fais stmte…

A: We assume that the differences of the distances are approximately normally distributed.

Q: The mileage a car got on 5 trips from Greenwood to Greenville was used to create a 90% confidence…

A: Solution-: Given: The 90% C.I. for the true mean mileage of such trips is (32.32,38.32) The…

Q: 1 POINT In a recent survey, a random sample of 450 families visiting a zoo were asked how…

A:

Q: You measure 28 turtles' weights, and find they have a mean weight of 75 ounces. Assume the…

A: sample size(n)=28Mean()=75standard deviation()=14.2confidence level=99%

Q: What proportion of new drivers fail the written portion of their driver's license examination? You…

A: Given Data: p=196/500=0.392   n=500   z-value corresponding to 95% Confidence level=1.96

Q: According to a report on consumer fraud and identity theft, Montana had 1447 complaints of identity…

A: Given that, x=1447,n=3643 The sample proportion is,

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: Given: Sample size, n=100 Number of adults having kids, x=84

Q: You want to estimate the proportion of park visitors that bring food to the park. If you took an SRS…

A: Given that sample size is n= 100 And x= 43 We know that, proportion, p= x/n p= 43/100 = 0.43…

Q: You measure 33 dogs' weights, and find they have a mean weight of 55 ounces. Assume the population…

A: It is given that Sample size n = 33 Sample mean M = 55 Population SD = 14 The critical value of Z at…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.