Eley-Rideal (E-R) Kinetic Mechanism A(g) + B (g) → C(g) + D (g) B B B B B A r = k 04 Өв A KAPA r = kPB ³ (1+ KAPA) ➤ When Kд is very large, the slope of rate versus PB is the rate constant k ➤ When Kд is low, the slope of rate versus Pg equal to KдPÅk B

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Chapter1: Introduction
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Assignment 1: derive the rate equation for the reaction based on Mars-van Krevelen Kinetic Mechanism and Eley-Rideal (E-R) Kinetic Mechanism

Eley-Rideal (E-R) Kinetic Mechanism
A(g) + B(g) → C(g) + D(g)
B
A
B B B B
C
r= k0₁0B
A
r =
KAPA
(1 + KAPA)
- крв'
➤When K is very large, the slope of rate versus PB is the rate constant k
➤When K is low, the slope of rate versus PB equal to KAPBK
A
Transcribed Image Text:Eley-Rideal (E-R) Kinetic Mechanism A(g) + B(g) → C(g) + D(g) B A B B B B C r= k0₁0B A r = KAPA (1 + KAPA) - крв' ➤When K is very large, the slope of rate versus PB is the rate constant k ➤When K is low, the slope of rate versus PB equal to KAPBK A
●
Mars-van Krevelen Kinetic Mechanism
Step 1:
A B
Reactants adsorb onto different sites, and the two surface
intermediates interact and reaction occurs. No site competition.
Step 2:
Example: Mars-van Krevelen Kinetic for CO oxidation over
copper oxide and iron oxide
Step 3:
A B A B
A + B → C
CO + 2 CuO → Cu₂O + CO₂
Cu₂O + FeO
2CuO + Fe
(12)O₂+ Fe FeO
rco = k₁ Pco Ⓒ
со
r = K₂Po₂¹/² (1-0)
CO + (½)O₂ → CO₂
Net reaction
K₁ Pcok₂ Po₂¹/2² (1-0)
=
r co
=
k₁ k₂ Pco Po,1/2
k₁pco + k₂Po₂¹/2
=
¹1/2
k₂Po₂¹
K₂Po+k₂Po₂¹/2
At low CO/02, the rate reduces to k₁pco
➤ At high CO/O2, the rate reduces to k₂Po₂¹/2
11
Transcribed Image Text:● Mars-van Krevelen Kinetic Mechanism Step 1: A B Reactants adsorb onto different sites, and the two surface intermediates interact and reaction occurs. No site competition. Step 2: Example: Mars-van Krevelen Kinetic for CO oxidation over copper oxide and iron oxide Step 3: A B A B A + B → C CO + 2 CuO → Cu₂O + CO₂ Cu₂O + FeO 2CuO + Fe (12)O₂+ Fe FeO rco = k₁ Pco Ⓒ со r = K₂Po₂¹/² (1-0) CO + (½)O₂ → CO₂ Net reaction K₁ Pcok₂ Po₂¹/2² (1-0) = r co = k₁ k₂ Pco Po,1/2 k₁pco + k₂Po₂¹/2 = ¹1/2 k₂Po₂¹ K₂Po+k₂Po₂¹/2 At low CO/02, the rate reduces to k₁pco ➤ At high CO/O2, the rate reduces to k₂Po₂¹/2 11
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