Electronic components are attached under a thin square plate and the all the energy dissipated by components is removed by water flow over the top surface. The plate length is 0.18 m and the thermophysical properties of water may be approximated as: k = 0.620 W/mK, Pr = 5.2, v = 0.96x10-6 m²/s water V m/s 20°C q" W/m² dissipated energy from the components Water flow velocity is 1.5 m/s and the amount of dissipated energy (q") from the components can be estimated as uniformly distributed heat flux of 80000 W/m?. One approach to analyze this problem is to assume the plate has an isothermal temperature as a boundary condition. Calculate the average isothermal plate temperature in °C for the given conditions If the boundary layer is 'tripped' and the flow over the plate is completely turbulent; what will be the average isothermal plate temperature in °C for this case? 25 30 || 35| 41 46 || 50|| 58 24 26 || 28 30 || 32 36 || 39
Electronic components are attached under a thin square plate and the all the energy dissipated by components is removed by water flow over the top surface. The plate length is 0.18 m and the thermophysical properties of water may be approximated as: k = 0.620 W/mK, Pr = 5.2, v = 0.96x10-6 m²/s water V m/s 20°C q" W/m² dissipated energy from the components Water flow velocity is 1.5 m/s and the amount of dissipated energy (q") from the components can be estimated as uniformly distributed heat flux of 80000 W/m?. One approach to analyze this problem is to assume the plate has an isothermal temperature as a boundary condition. Calculate the average isothermal plate temperature in °C for the given conditions If the boundary layer is 'tripped' and the flow over the plate is completely turbulent; what will be the average isothermal plate temperature in °C for this case? 25 30 || 35| 41 46 || 50|| 58 24 26 || 28 30 || 32 36 || 39
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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heat transfer
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![Electronic components are attached under a thin square plate and the all the energy dissipated by components is removed by water flow
over the top surface. The plate length is 0.18 m and the thermophysical properties of water may be approximated as:
k = 0.620 W/mK, Pr = 5.2, v = 0.96x10-6 m²/s
water
V m/s
20°C
q" W/m²
dissipated energy from
the components
Water flow velocity is 1.5 m/s and the amount of dissipated energy (q") from the components can be estimated as uniformly distributed
heat flux of 80000 W/m?. One approach to analyze this problem is to assume the plate has an isothermal temperature as a
boundary condition.
Calculate the average isothermal plate temperature in °C for the given conditions
If the boundary layer is 'tripped' and the flow over the plate is completely turbulent; what will be the average isothermal plate
temperature in °C for this case?
25 30 || 35| 41
46 || 50|| 58
24 26 || 28
30 || 32
36 || 39](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb61a16b-d40e-4602-b13f-3f2d287da9c0%2F96322b49-a836-40e7-81df-658405299796%2Fkq5s3cn_processed.png&w=3840&q=75)
Transcribed Image Text:Electronic components are attached under a thin square plate and the all the energy dissipated by components is removed by water flow
over the top surface. The plate length is 0.18 m and the thermophysical properties of water may be approximated as:
k = 0.620 W/mK, Pr = 5.2, v = 0.96x10-6 m²/s
water
V m/s
20°C
q" W/m²
dissipated energy from
the components
Water flow velocity is 1.5 m/s and the amount of dissipated energy (q") from the components can be estimated as uniformly distributed
heat flux of 80000 W/m?. One approach to analyze this problem is to assume the plate has an isothermal temperature as a
boundary condition.
Calculate the average isothermal plate temperature in °C for the given conditions
If the boundary layer is 'tripped' and the flow over the plate is completely turbulent; what will be the average isothermal plate
temperature in °C for this case?
25 30 || 35| 41
46 || 50|| 58
24 26 || 28
30 || 32
36 || 39
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