Electric power: is often used to generate heat. You might use an electric kettle to heat up 340 g of water for a cup of tea. Water has a very high heat capacity, so this uses a lot of energy. We can use the specific heat of water (water 4186 J/kg°C) to calculate the total energy E required to heat the water: E = cm▲T, where c is specific heat, m is the mass of water, and AT is the change in temperature. Assume that the water starts at room temperature (25 °C). = a. How much energy (in joules) is required to heat the water to boiling (100 °C)? b. If the price for electricity is 10.78 ¢/kWh from Pacific Power in Oregon, how many cups of tea can you make for $1? (Assume that water and tea are free, and that the water absorbs all of the electric power delivered.) Your electric kettle operates at a constant current of 15 A and a constant voltage of 120 V. C. i. How much energy does it consume in five minutes of continuous operation? ii. How many cups of tea can this heat? iii. How much would this energy cost using the Pacific Power rate of 10.78 ¢/kWh?

Introductory Circuit Analysis (13th Edition)
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Electric power is often used to generate heat. You might use an electric kettle to heat up 340 g of water for a cup of tea. Water has a very high heat capacity, so this uses a lot of energy. We can use the specific heat of water (\(c_{water} = 4186 \, \text{J/kg°C}\)) to calculate the total energy \(E\) required to heat the water: \(E = cm\Delta T\), where \(c\) is specific heat, \(m\) is the mass of water, and \(\Delta T\) is the change in temperature. Assume that the water starts at room temperature (25 °C).

a. How much energy (in joules) is required to heat the water to boiling (100 °C)?

b. If the price for electricity is 10.78 ¢/kWh from Pacific Power in Oregon, how many cups of tea can you make for $1? (Assume that water and tea are free, and that the water absorbs all of the electric power delivered.)

c. Your electric kettle operates at a constant current of 15 A and a constant voltage of 120 V.
   i. How much energy does it consume in five minutes of continuous operation?
   ii. How many cups of tea can this heat?
   iii. How much would this energy cost using the Pacific Power rate of 10.78 ¢/kWh?
Transcribed Image Text:Electric power is often used to generate heat. You might use an electric kettle to heat up 340 g of water for a cup of tea. Water has a very high heat capacity, so this uses a lot of energy. We can use the specific heat of water (\(c_{water} = 4186 \, \text{J/kg°C}\)) to calculate the total energy \(E\) required to heat the water: \(E = cm\Delta T\), where \(c\) is specific heat, \(m\) is the mass of water, and \(\Delta T\) is the change in temperature. Assume that the water starts at room temperature (25 °C). a. How much energy (in joules) is required to heat the water to boiling (100 °C)? b. If the price for electricity is 10.78 ¢/kWh from Pacific Power in Oregon, how many cups of tea can you make for $1? (Assume that water and tea are free, and that the water absorbs all of the electric power delivered.) c. Your electric kettle operates at a constant current of 15 A and a constant voltage of 120 V. i. How much energy does it consume in five minutes of continuous operation? ii. How many cups of tea can this heat? iii. How much would this energy cost using the Pacific Power rate of 10.78 ¢/kWh?
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