El cálculo de la integral, S sin' (z) dz es equivalente a Seleccione una: O a. - sin (2a)+ S [1+ cos (4r)] dx] O b.+sin (2x) – S(1- cos (4.x)] da] cos (2) +C O dr- sin (2) + + sin ()] + C O ez+sin (2a)-1+ cos (4r)) dr]
El cálculo de la integral, S sin' (z) dz es equivalente a Seleccione una: O a. - sin (2a)+ S [1+ cos (4r)] dx] O b.+sin (2x) – S(1- cos (4.x)] da] cos (2) +C O dr- sin (2) + + sin ()] + C O ez+sin (2a)-1+ cos (4r)) dr]
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![El cálculo de la integral,
der
S sin' (z) dz,
es equivalente a
Seleccione una:
O a -sin (2r) + S1+ cos (4r)] da]
O b.+ sin (2a)- S[1-
cos (4x)] da
cas (1)
+C
Od r- sin (2)+ + sin ()] + C
O e. + sin (2)-J1+cos (4r) dr]
SUS](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F008e1cff-74f7-42f9-a2df-c05bbe1e1b63%2F2d956bf1-37fc-40f5-816e-f77620ea1107%2Fjygqwm9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:El cálculo de la integral,
der
S sin' (z) dz,
es equivalente a
Seleccione una:
O a -sin (2r) + S1+ cos (4r)] da]
O b.+ sin (2a)- S[1-
cos (4x)] da
cas (1)
+C
Od r- sin (2)+ + sin ()] + C
O e. + sin (2)-J1+cos (4r) dr]
SUS
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