Educational Television In a random sample of 190 people, 150 said that they watched educational television. Find the 95% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places. O

Q: Claim: Most adults would erase all of their personal information online if they could. A software…

A: we have to test that if most of adults erase all of their personal information if they could sample…

Q: Use the sample data and confidence level to construct the confidence interval estimate of the…

A: We have given that the sample size 550, favourable number of cases X=385 and confidence level is…

Q: Claim: Most adults would erase all of their personal information online if they could. A software…

A:

Q: standard deviation is $17.40.

A: We have given that  Sample size n =55 Sample mean =136 Standard deviation =17.40

Q: Claim: Most adults would erase all of their personal information online if they could. A software…

A: Given,   Sample size = 562 Sample proportion = 0.58   The null and alternative hypothesis is:

Q: The confidence level specifies the probability that the ________ will cover the true population…

A: We have to find defination of confidence level which is correct from given option.

Q: Use the confidence interval to find the margin of error and the sample mean.   (1.44,1.98)   The…

A: Given that  Confidence interval=(1.44,1.98)

Q: Claim: Most adults would erase all of their personal information online if they could. A software…

A: Given: n=582 and p=58%=0.58. From the given information,H0:p=0.5H1:p>0.5

Q: esc In a 2013 poll, it was found that 0.78 of Americans cover their mouth when sneezing. A…

A: a)The p-value represents the probability of obtaining results as extreme as the observed results,…

Q: In a survey of 3700 TV viewers, 834 said they watch network news programs. Find the margin of error…

A: Solution

Q: Express the confidence interval (78.7 % , 96.3 % ) in the form of p+ ME. %士 Question Help: Video…

A: Given,confidence interval(CI)=(78.7% , 96.3%)

Q: A sociologist plans to conduct a survey to estimate the percentage of adults who believe in…

A: Given thatMargin of error (E) = 4% = 0.04Significance level (α) = 1 - 0.99 = 0.01

Q: ..... The value of the test statistic is (Round to two decimal places as needed.)

A: Given :   sample size, n = 480 population proportion,p= 0.5 sample proportion…

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given, Total size n = 140 No of ppl smoke x = 35 proportion p = xn = 35140 = 0.25 99% confidence…

Q: Use the histogram below to complete the statements. The mean of the data set is 50 and the standard…

A: Identify the correct option to estimate the probabilities of the given histogram. The correct option…

Q: Fast-Food Bills for Drive-Thru Customers A random sample of 42 cars in the drive-thru of a popular…

A: From the provided information, Sample size (n) = 42 Population standard deviation (σ) = 6.47 Sample…

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: From the provided information, Sample size (n) = 70 and x = 21 Sample proportion (p̂) = x/n = 21/70…

Q: VIupw v This question: 1 point(s) possIble A survey was conducted that asked 1013 people how many…

A:

Q: Assume that a randomly selected subject is given a bone density test. Bone density test scores are…

A: Given that: Z is standard normal Distributed with i.e. mean µ =0 and standard deviation σ =1 now…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A: Given, The best sample proportion is, Critical value: Using the z-table, the z-critical value for…

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A:

Q: In a survey of 2587 adults in a recent​ year, 1241 say they have made a New​ Year's resolution.…

A: From the provided information Sample size (n) = 2587 1241 say they have made a New​ Year's…

Q: We asked 101 people to report the number of cars they've ever owned. The results are a mean of 4 and…

A: Given data,n=101x=4σ=1z-value at 90% confidence is Zc=1.645

Q: JA company conducts a survey to determine the gender of car users across the different car types.…

A: Given that    Car Truck  SUV VAN Male 85 96 45 6 Female 110 75 60 3 Confidence level=90%…

Q: Gasoline Use A random sample of 49 drivers used on average 754 gallons of gasoline per year. The…

A: The sample size is 49, sample mean is 754 and population standard deviation is 33.

Q: Educational Television In a random sample of 190 people, 145 said that they watched educational…

A: The answer is given below:

Q: Construct a confidence interval for p, - p, at the given level of confidence. X, = 377, n, = 533, x,…

A:

Q: . If there were a total of 500 respondents, how many of them are expected to be more than 72 inches…

A: Given that mean=65.4,s.d=2.9

Q: Claim: Most adults would erase all of their personal information online if they could. A software…

A: The sample size is 542, sample proportion is 0.58, and population proportion is 0.5.

Q: Claim: Most adults would erase all of their personal information online if they could. A software…

A:

Q: Use the confidence interval to find the margin of error and the sample mean.   (0.676,0.800)

A: The margin of error is the most common term which we use in a confidence interval. It is the degree…

Q: In a survey of 3054 ​adults, 1414 say they have started paying bills online in the last year.…

A: From the provided information, Sample size (n) = 3054 adults Out of which 1414 say they have started…

Q: Claim: Most adults would erase all of their personal information online if they could. A software…

A: Solution: From the given information, p-hat = 0.61 and n = 593. The claim is that most adults would…

Q: Fill in the blank. A random sample of 60 business students required an average of 50.7 minutes to…

A: We have given that  Sample size n = 60 Sample mean =50.7 Population standard deviation =10.4…

Q: Construct the confidence interval for the population mean p. c= 0.95, x= 15.4, a = 3.0, and n= 65 A…

A: Provided information: Sample mean = 15.4 Standard deviation = 3.0 Sample size = 65 c = 0.95

Q: on In a random sample of 205 people, 142 said that they watched educational television. Find the 99%…

A: given data, n=205x=142p^=xn=142205=0.6927CI=0.99α=1-0.99=0.01Zc:=Zα/2=Z0.01/2= Z0.0050=2.576 [from…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.