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easure the velocity of air at the center of a duct aving a 10 cm diameter. A tube mounted at the enter of the duct has a 2 mm diameter and is P= 150 kPa tached to one leg of a inclined-tube manometer. pressure tap in the wall of the duct is connected the other end of the inclined-tube manometer. T 20°C he well of the inclined-tube manometer is ufficiently large that the elevation of the fluid in it bes not change significantly when fluid moves up e leg of the manometer. The air in the duct is at a pressure of 15 anometer liquid has a specific gravity of 0.7, and the slope of the leg ere is no flow in the duct, the liquid surface in the manometer lies at 2. clined scale. When there is flow in the duct, the liquid moves up to 6. clined scale. Find the velocity of the air in the duct. Assuming a unife ofile in the duct, calculate the rate of flow of the air. Neglect all losses. 30 -6.7 cm

easure the velocity of air at the center of a duct aving a 10 cm diameter. A tube mounted at the enter of the duct has a 2 mm diameter and is P= 150 kPa tached to one leg of a inclined-tube manometer. pressure tap in the wall of the duct is connected the other end of the inclined-tube manometer. T 20°C he well of the inclined-tube manometer is ufficiently large that the elevation of the fluid in it bes not change significantly when fluid moves up e leg of the manometer. The air in the duct is at a pressure of 15 anometer liquid has a specific gravity of 0.7, and the slope of the leg ere is no flow in the duct, the liquid surface in the manometer lies at 2. clined scale. When there is flow in the duct, the liquid moves up to 6. clined scale. Find the velocity of the air in the duct. Assuming a unife ofile in the duct, calculate the rate of flow of the air. Neglect all losses. 30 -6.7 cm

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The apparatus shown in the figure is used to measure the velocity of air at the center of a duct having a 10 cm diameter. A tube mounted at the center of the duct has a 2 mm diameter and is 10 cm p = 150 kPa T= 20°C attached to one leg of a inclined-tube manometer. A pressure tap in the wall of the duct is connected to the other end of the inclined-tube manometer. The well of the inclined-tube manometer is well 30 sufficiently large that the elevation of the fluid in it does not change significantly when fluid moves up the leg of the manometer. The air in the duct is at a pressure of 150 kPa. The manometer liquid has a specific gravity of 0.7, and the slope of the leg is 30. When there is no flow in the duct, the liquid surface in the manometer lies at 2.3 cm on the inclined scale. When there is flow in the duct, the liquid moves up to 6.7 cm on the inclined scale. Find the velocity of the air in the duct. Assuming a uniform velocity profile in the duct, calculate the rate of flow of the air. Neglect all losses. S = 0.7 -6.7 cm -2.3 cm
Transcribed Image Text:The apparatus shown in the figure is used to measure the velocity of air at the center of a duct having a 10 cm diameter. A tube mounted at the center of the duct has a 2 mm diameter and is 10 cm p = 150 kPa T= 20°C attached to one leg of a inclined-tube manometer. A pressure tap in the wall of the duct is connected to the other end of the inclined-tube manometer. The well of the inclined-tube manometer is well 30 sufficiently large that the elevation of the fluid in it does not change significantly when fluid moves up the leg of the manometer. The air in the duct is at a pressure of 150 kPa. The manometer liquid has a specific gravity of 0.7, and the slope of the leg is 30. When there is no flow in the duct, the liquid surface in the manometer lies at 2.3 cm on the inclined scale. When there is flow in the duct, the liquid moves up to 6.7 cm on the inclined scale. Find the velocity of the air in the duct. Assuming a uniform velocity profile in the duct, calculate the rate of flow of the air. Neglect all losses. S = 0.7 -6.7 cm -2.3 cm
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