Early one cool (50.9 °F) morning you start on a bike ride with the atmospheric pressure at 14.7 lb in 2 and the tire gauge pressure at 39.4 lb in 2. (Gauge pressure is the amount that the pressure exceeds atmospheric pressure.) By late afternoon, the air had warmed up considerably, and in combination with the heat generated by tire friction, the temperature inside the tire has climbed to 94.1°F. What will the tire gauge now read, assuming that the volume of the air in the tire and the atmospheric pressure have not changed?

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Early one cool (50.9 °F) morning you start on a bike ride with the atmospheric pressure at 14.7 lb in 2 and the tire gauge pressure
at 39.4 lb in2. (Gauge pressure is the amount that the pressure exceeds atmospheric pressure.) By late afternoon, the air had warmed
up considerably, and in combination with the heat generated by tire friction, the temperature inside the tire has climbed to 94.1 °F.
What will the tire gauge now read, assuming that the volume of the air in the tire and the atmospheric pressure have not changed?
Gauge pressure =
i
Ib in 2
Transcribed Image Text:Early one cool (50.9 °F) morning you start on a bike ride with the atmospheric pressure at 14.7 lb in 2 and the tire gauge pressure at 39.4 lb in2. (Gauge pressure is the amount that the pressure exceeds atmospheric pressure.) By late afternoon, the air had warmed up considerably, and in combination with the heat generated by tire friction, the temperature inside the tire has climbed to 94.1 °F. What will the tire gauge now read, assuming that the volume of the air in the tire and the atmospheric pressure have not changed? Gauge pressure = i Ib in 2
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