ead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is eased from rest at a height h = 3.40R. R (a) What is its speed at point ? (Use the following as necessary: the acceleration due to gravity g, and R.) √2.8gR v= (b) How large is the normal force on the bead at point if its mass is 5.50 grams? magnitude XN direction downward

ead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is eased from rest at a height h = 3.40R. R (a) What is its speed at point ? (Use the following as necessary: the acceleration due to gravity g, and R.) √2.8gR v= (b) How large is the normal force on the bead at point if its mass is 5.50 grams? magnitude XN direction downward

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is
released from rest at a height h = 3.40R.
R
(a) What is its speed at point ? (Use the following as necessary: the acceleration due to gravity g, and R.)
V = √ 2.8gR
(b) How large is the normal force on the bead at point if its mass is 5.50 grams?
magnitude
X N
direction downward ✓

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