Each plate of a parallel-plate air-filled capacitor has an area of 0.0020 m2, and the separation of the plates is 0.020 mm. An electric field of 3.9x106 V/m is present between the plates. What is the surface charge density on the plates? HINT:  (where E = electric field, V = Potential difference/Voltage, and d = distance between plates) Also note that 1 N/C = 1 V/m. (V/m is just another unit for electric field)
Each plate of a parallel-plate air-filled capacitor has an area of 0.0020 m2, and the separation of the plates is 0.020 mm. An electric field of 3.9x106 V/m is present between the plates. What is the surface charge density on the plates? HINT:  (where E = electric field, V = Potential difference/Voltage, and d = distance between plates) Also note that 1 N/C = 1 V/m. (V/m is just another unit for electric field)
Related questions
Question
Each plate of a parallel-plate air-filled capacitor has an area of 0.0020 m2, and the separation of the plates is 0.020 mm. An electric field of 3.9x106 V/m is present between the plates. What is the surface charge density on the plates?
HINT:  (where E = electric field, V = Potential difference/Voltage, and d = distance between plates)
Also note that 1 N/C = 1 V/m. (V/m is just another unit for electric field)
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps