Each of a sample of 176 residents selected from a small town is asked how much money he or she spent last week on state lottery tickets. 130 of the residents responded with $0. The mean expenditure for the remaining residents was $21. The largest expenditure was $210. Step 5 of 5: What proportion of the sample did not purchase any lottery tickets? Express your answer as a simplified fraction or as a value rounded to one decimal place.
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- Each of a sample of 176 residents selected from a small town is asked how much money he or she spent last week on state lottery tickets. 130 of the residents responded with $0. The mean expenditure for the remaining residents was $21. The largest expenditure was $210. Step 2 of 5: What is the median of the data?Each of a sample of 176 residents selected from a small town is asked how much money he or she spent last week on state lottery tickets. 130 of the residents responded with $0. The mean expenditure for the remaining residents was $21. The largest expenditure was $210. Step 3 of 5: What is the mode of the data?A polling company reported that 33% of 2286 surveyed adults said that they play football. Complete parts (a) through (d) below. C a. What is the exact value that is 33% of 2286? The exact value is (Type an integer or a decimal.) b. Could the result from part (a) be the actual number of adults who said that they play football? Why or why not? O A. No, the result from part (a) could not be the actual number of adults who said that they play football because that is a very rare activity. O B. Yes, the result from part (a) could be the actual number of adults who said that they play football because the results are statistically significant. O C. Yes, the result from part (a) could be the actual number of adults who said that they play football because the polling numbers are accurate. O D. No, the result from part (a) could not be the actual number of adults who said that they play football because a count of people must result in a whole number. c. What could be the actual number of…
- The average expenditure on Valentine's Day was expected to be $100.89 (USA Today, February 13, 2006). Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 44 male consumers was $137.38, and the average expenditure in a sample survey of 35 female consumers was $65.11. Based on past surveys, the standard deviation for male consumers is assumed to be $35, and the standard deviation for female consumers is assumed to be $12. The z value is 2.576. Round your answers to decimal places. b. At 99% confidence, what is the margin of error? c. Develop a 99% confidence interval for the difference between the two population means.A polling company reported that 53% of 2286 surveyed adults said that they play football. Complete parts (a) through (d) below. C a. What is the exact value that is 53% of 2286? The exact value is (Type an integer or a decimal.) b. Could the result from part (a) be the actual number of adults who said that they play football? Why or why not? O A. No, the result from part (a) could not be the actual number of adults who said that they play football because a count of people must result in a whole number. O B. Yes, the result from part (a) could be the actual number of adults who said that they play football because the results are statistically significant. O C. No, the result from part (a) could not be the actual number of adults who said that they play football because that is a very rare activity. O D. Yes, the result from part (a) could be the actual number of adults who said that they play football because the polling numbers are accurate. c. What could be the actual number of…A political pollster wants to ensure that their poll on attitudes toward separation of church and state gets responses from all major religious groups. What kind of sampling method should be used?
- 2. A city had an unemployment rate of 7%. The mayor pledged to lower this figure and supported programs to decrease unemployment. A group of citizens wanted to test with 0.032 label of significance if the unemployment rate had actually decreased, so they obtained a random sample of 500 citizens to see what proportion of the sample was unemployed. Only 32 citizens in the above sample is still unemployed. What is the probability of Type II error if the actual unemployment rate is 6.5% please don't use software everything needs to be done by hand. Explain because I don't understand my professor. Note:- Do not provide handwritten solution. Maintain accuracy and quality in your answer. Take care of plagiarism. Answer completely. You will get up vote for sure.According to Wine-Searcher, wine critics generally use a wine-scoring scale to communicate their opinions on the relative quality of wines. Wine scores range from 0 to 100, with a score of 95 – 100 indicating a great wine, 90 – 94 indicating an outstanding wine, 85 – 89 indicating a very good wine, 80 – 84 indicating a good wine, 75 - 79 indicating a mediocre wine, and below 75 indicating that the wine is not recommended. Random ratings of a pinot noir recently produced by a newly established vineyard in 2018 follow: Excel File: data07-11.xlsx 87 91 86 82 72 91 60 77 80 79 83 96 a. Develop a point estimate of mean wine score for this pinot noir (to 2 decimals). b. Develop a point estimate of the standard deviation for wine scores received by this pinot noir (to 4 decimals).Question One a) The University of the East Europe is interested in the overall performance of its students in the academic year 2020/2021. There were 1460 students registered for this academic year. The University decides to select a sample of 150 students from each of the 5 faculties- Science, Medicine, Law, Social Science and Humanities in proportion to the number of students in each faculty. Identify the population of interest for this scenario. ii. i. Identify the sampling technique used by the researcher. State one advantage and one disadvantage of the sampling technique described in the given scenario. If the medical faculty has 584 students registered, calculate how many medical students would be part of the sample of 150. iii. iv.
- 8.The questions has two parts: A departmental store sells stereo systems, television sets and radios. The percentage distribution of the total sales volume (in rupees) is estimated as 30 per cent stereos, 50 per cent televisions and 20 per cent radios. The prices of one stereo, one television and one radio in 1990 were $ 20,000, $15,000 and $ 500 respectively while their respective prices in 1995 were $25,000, $ 20,000 and $ 800. A weighted price index for 1995 with base 1990 is to be computed. (i) Which index number formula is appropriate, why? (ii) Compute the index.A simple random sample of 8 employees of a corporation provided the following information. Employee Age Gender 1 2 3 21 37 26 W M W 4 5 6 7 8 44 48 50 25 22 W W M M M (a) Determine the point estimate for the average age of all employees. (b) What is the point estimate for the standard deviation of the population? (Round your answer to four decimal places.) (c) Determine a point estimate for the proportion of all employees who are female.