Each ionizable group of an amino acid can exist in one of two states, charged or neutral. The electric charge on the functional group is determined by the relationship between its pKą and the pH of the solution. This relationship is described by the Henderson-Hasselbalch equation. Histidine has three ionizable functional groups. Complete the equilibrium equations by assigning the proper pKą for each ionization and the net charge on the histidine molecule in each ionization state. H || H,N*-C-C-OH H|| H,N*-C-C-o- H|| H,N*-C-C-o- H|| H,N-C-C-o- CH, CH, CH, CH, HN HN N -NH -NH -NH -NH Answer Bank pKa = 6.0 -1 pK = 9.17 +2 -2 +1 pk = 7.59 pk = 1.8 %3D 1 1
Each ionizable group of an amino acid can exist in one of two states, charged or neutral. The electric charge on the functional group is determined by the relationship between its pKą and the pH of the solution. This relationship is described by the Henderson-Hasselbalch equation. Histidine has three ionizable functional groups. Complete the equilibrium equations by assigning the proper pKą for each ionization and the net charge on the histidine molecule in each ionization state. H || H,N*-C-C-OH H|| H,N*-C-C-o- H|| H,N*-C-C-o- H|| H,N-C-C-o- CH, CH, CH, CH, HN HN N -NH -NH -NH -NH Answer Bank pKa = 6.0 -1 pK = 9.17 +2 -2 +1 pk = 7.59 pk = 1.8 %3D 1 1
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Each ionizable group of an amino acid can exist in one of two states, charged or neutral. The electric charge on the
functional group is determined by the relationship between its pKą and the pH of the solution. This relationship is described
by the Henderson-Hasselbalch equation.
Histidine has three ionizable functional groups. Complete the equilibrium equations by assigning the proper pKą for each
ionization and the net charge on the histidine molecule in each ionization state.
H ||
H,N*-C-C-OH
H||
H,N*-C-C-o-
H||
H,N*-C-C-o-
H||
H,N-C-C-o-
CH,
CH,
CH,
CH,
HN
HN
N
-NH
-NH
-NH
-NH
Answer Bank
pK, = 6.0
-1
pк, - 9.17
+2
-2
+1
pK, = 7.59
pK, = 1.8
%3D
1
1
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