Order: Potassium chloride 30 mEq, PO, daily with foodAvailable: Potassium chloride 20 mEq/15 mLHow many milliliters of potassium chloride will the patient receive? __ mLRound to the nearest tenth. Each 15 ml (tablespoon)contains: PotassiumChloride, USP... 20 mEqInactive Ingredients:citric acid, FD&C Yellow #6,glycerin, methylparaben,natural/artificial orangeflavor, propylene glycol,propylparaben, purifiedwater, sodium citratedihydrate, sucralose.Dosage andAdministration: Seeaccompanying prescribinginformation.Store at 25°C (77°F);excursions permitted to15°-30°C (50°-86°F).KEEP THIS AND ALLMEDICATION OUT OF THEREACH OF CHILDREN.NDC 0603-1542-58byPotassium ChlorideChloride QUALITESTPHARMACEUTICALSP2/15 PDOral Solution,USP, 10%20 mEq per 15 mLDILUTE PRIOR TOADMINISTRATIONRx only473 mLQualitestLEHIGH VALLEY TECHNOLOGIES, INC.ALLENTOWN, PA 11023 0603-1542-589Lot No.:Exp Data NO VARNISH

The objective of this question is to calculate the volume of potassium chloride solution the patient will receive based on the doctor's order and the available concentration of the medication.First, we need to understand the doctor's order. The doctor has ordered 30 mEq of potassium chloride to be administered orally once daily with food.Next, we need to consider the available concentration of the medication. The available concentration is 20 mEq in 15 mL of solution. This means that for every 15 mL of solution, there are 20 mEq of potassium chloride.To find out how many milliliters of the solution the patient will receive, we need to set up a proportion. The proportion is set up as follows: 20 mEq/15 mL = 30 mEq/x mL, where x is the volume of the solution that contains 30 mEq of potassium chloride.By cross-multiplying, we get 20x = 450. Solving for x, we get x = 450/20 = 22.5 mL.However, the question asks us to round to the nearest tenth. Therefore, the patient will receive 22.5 mL of potassium chloride solution.The patient will receive 22.5 mL of potassium chloride solution based on the doctor's order of 30 mEq and the available concentration of 20 mEq in 15 mL of solution. This calculation was done by setting up a proportion and solving for the unknown.