E28. According to a safety code, the maximum allowable current for a 14 gauge copper wire (diameter, 1.628 mm) is 15 A, and it is 5 A for an 18 gauge wire (diameter 1.024 mm). What would be the potential difference between the ends of a 10m length of each type of wire for maximum current? ∆V14 = 1.23 V ; ∆V18 = 1.03 V Please show steps and formulas for my own understanding.
E28. According to a safety code, the maximum allowable current for a 14 gauge copper wire (diameter, 1.628 mm) is 15 A, and it is 5 A for an 18 gauge wire (diameter 1.024 mm). What would be the potential difference between the ends of a 10m length of each type of wire for maximum current? ∆V14 = 1.23 V ; ∆V18 = 1.03 V Please show steps and formulas for my own understanding.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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E28. According to a safety code, the maximum allowable current for a 14 gauge copper wire (diameter, 1.628 mm) is 15 A, and it is 5 A for an 18 gauge wire (diameter 1.024 mm). What would be the potential difference between the ends of a 10m length of each type of wire for maximum current?
∆V14 = 1.23 V ; ∆V18 = 1.03 V
Please show steps and formulas for my own understanding.
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