The following output summarizes the results for a one-way analysis of varlance experiment in which the treatments were threedifferent hybrid cars and the variable measured was the miles per gallon (mpg) obtained while driving the same route. (You may find ituseful to reference the glable.)Hybrid 1129, 01 20Hybrid 2: 235, m₂ 15Hybrid 3:2 22, ny = 18Source of VariationBetween Groupswithin GroupsTotaldfSS1,068.271,483.702,551.97o. At the 5% significance level, can we conclude that average mpg differs between the hybrids?2MS534.1429.675052Population MeanDifferencesO Yes. since the p-value is less than the significance level.O Yes, since the p-value is not less than the significance level.ONo, since the p-value is less than the significance level.Confidence Interval15.00ONo, since the p-value is not less than the significance level.b. Use Tukey's HSD method at the 5% significance level to determine which hybrids' means differ. (If the exact value for me is notfound in the table, then round down. Negative values should be indicated by a minus sign. Round your answers to 2 decimalplaces)p-value0.0000Can we conclude that thehybrids' means differ?

Here the dependent variable is miles per gallon (mpg). The independent variable is three different…

Answered: e. At the 5% significance level, can we…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the proportion of men who own cats is significantly different than 80% at the 0.01 significance level.The null and alternative hypothesis would be: H0:μ=0.8H0:μ=0.8H1:μ>0.8H1:μ>0.8 H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 H0:p=0.8H0:p=0.8H1:p<0.8H1:p<0.8 H0:μ=0.8H0:μ=0.8H1:μ<0.8H1:μ<0.8 H0:p=0.8H0:p=0.8H1:p>0.8H1:p>0.8 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 The test is: two-tailed left-tailed right-tailed Based on a sample of 35 people, 76% owned catsThe test statistic is: (to 2 decimals)The positive critical value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.05 significance level. The null and alternative hypothesis would be: H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF The test is: left-tailed right-tailed two-tailed Based on a sample of 40 men, 25% owned catsBased on a sample of 40 women, 30% owned cats The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Use the following ANOVA table for regression to answer the questions. Analysis of Variance Source DF SS MS F P Regression 3377.5 3377.5 18.1 0.000 Residual Error 174 32468.4 186.6 Total 175 35845.9 Give the F-statistic and p-value. Enter the exact answers. The F-statistic is i The p-value is i eTextbook and Media Hint 63°F Cla Type here to search
Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.1 significance level.The null and alternative hypothesis would be: H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 H0:p≤0.8H0:p≤0.8H1:p>0.8H1:p>0.8 H0:p≥0.8H0:p≥0.8H1:p<0.8H1:p<0.8 H0:μ≤0.8H0:μ≤0.8H1:μ>0.8H1:μ>0.8 H0:μ≥0.8H0:μ≥0.8H1:μ<0.8H1:μ<0.8 The test is: right-tailed left-tailed two-tailed Based on a sample of 200 people, 87% owned catsThe p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
According to a recent poll the percentage of Americans who would vote for the incumbent president is 53%. If a random sample of 100 people in New York results in 45% who would vote for the incumbent, test the claim that the percentage of people in New York who would vote for the incumbent president is different from 53%. Use a 0.10 significance level.H0: p = 0.53. Ha: p ≠ 0.53.α = 0.10Test statistic: z = -1.60. P-Value = 0.1090State your conclusion about H0.
According to a recent poll, the percentage of Americans who would vote for the incumbent president is 53%. If a random sample of 100 people in New York results in 45% who would vote for the incumbent, test the claim that the percentage of people in New York who would vote for the incumbent president is different from 53%. Use the following results and a 0.10 significance level to state your decision about H0. H0 : p=0.53 H1 : p≠0.53 test statistic: z = -1.6 p value = 0.1090
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.1 significance level. The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF The test is: right-tailed left-tailed two-tailed Based on a sample of 40 men, 45% owned catsBased on a sample of 40 women, 70% owned cats The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level. The null and alternative hypothesis would be: Ho: p= 0.8 Ho: ≤ 0.8 Hop: 0.8 Ho:p> 0.8 Ho: 0.8 Ho:p 0.8 H₁:µ 0.8 H₁:p 0.8 The test is: right-tailed two-tailed left-tailed = Based on a sample of 300 people, 82% owned cats The p-value is: (to 2 decimals)
Test the claim that the proportion of men who own cats is significantly different than 80% at the 0.1 significance level.The null and alternative hypothesis would be: H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 H0:p=0.8H0:p=0.8H1:p>0.8H1:p>0.8 H0:μ=0.8H0:μ=0.8H1:μ<0.8H1:μ<0.8 H0:μ=0.8H0:μ=0.8H1:μ>0.8H1:μ>0.8 H0:p=0.8H0:p=0.8H1:p<0.8H1:p<0.8 H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 The test is: two-tailed right-tailed left-tailed Based on a sample of 100 people, 87% owned catsThe test statistic is: (to 2 decimals)The positive critical value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the mean GPA of night students is significantly different than 3.3 at the 0.2 significance level. The null and alternative hypothesis would be: Ho:p0.825 H p 3.3 H p 0.825 H p <3.3 H:p 3.3 The test is: right-tailed two-tailed left-tailed Based on a sample of 80 people, the sample mean GPA was 3.33 with a standard deviation of 0.04 The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Is this p-value significant at the 10% significance level? Is it significant at the 5% significance level? Compare the answers to these questions to your answers to parts (g) and (i) in two complete sentences.

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